LetTjkmn be the tensor in (5.8). This is a4th -rank tensor and so has 34=81 components. Most of the components are zero. Find the nonzero components and their values. Hint: See discussion after(5.8) .

Short Answer

Expert verified

The non-zero components are mentioned below:

Tjkjk=1Tjkkj=1

Step by step solution

01

Given Information

The 4th-rank tensorTjkmn .

02

Definition of a Cartesian tensor

The first rank tensor is just a vector. A tensor of second rank has nine components (in three dimensions) in every rectangular coordinate system.

03

Find the nonzero components

Formula states that Tjkmn=δjmδknδjrδkm.

If k=j,then the formula becomes as follows.

Tjkmn=δjmδknδjrδkm=0

If ,then the formula becomes as follows.

Tjkmn=δjmδknδjrδkm=0

Tjkmn0for the following conditions mentioned below.

1)j=mk=n2)j=nk=m

Or jk.

There are six pairs, in which exactly two pairs satisfy the equation.

Hence the non-zero components are mentioned above

Tjkjk=1Tjkkj=1

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