Write the transformation equations to show that ∇×Vis a pseudo vector if Vis a vector. Hint:See equations (5.13), (6.2), and (6.3).

Short Answer

Expert verified

The transformation equation is (∇×V)α'=(detA)aαi(∇×V)i

Step by step solution

01

Given information.

Matrix definitions are given.

02

Definition of a rotation matrix.

The rotation matrix is defined in this way.

[cosϕ-sinϕsinϕcosϕ]

03

Define a vector and an orthogonal matrix.

Define to be a vector. Define an orthogonal matrix denoting proper or improper rotation. Write the result for proper and improper rotations.

∂∂xi'=aij∂∂xj

04

Continue evaluations.

Continue with evaluations.

∇×Vα'=ε'αβγ∂∂Xβ'Vγ'=detAaαiaβjaγkεijkaβm∂∂Xmaγnvn=detAaαiaβjaβmaγkaγnεijk∂∂Xmvn

Continue the simplification.

∇×Vα'=detAaαi∂jm∂knεijk∂∂Xmvn=detAaαiεijk∂∂Xmvk=detAaαi∇×Vi

This implies that∇×Vis a pseudo vector. Since A is defined to be orthogonal, write its result.

aβjaβm=δjmATA=I

Therefore, write the result.

(∇×V)α'=(detA)aαi(∇×V)i

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