Expand the triple product for a=ω×(ω×r) given in the discussion of Figure 3.8. If is perpendicular to w(Problem 16), show that a=ω2r, and so find the elementary result that the acceleration is toward the center of the circle and of magnitude v2r.

Short Answer

Expert verified

The acceleration a=ωω.rrω2

a=v2r Is proved.

Step by step solution

01

Given condition

The given condition is, a=ww.rrw2.

02

Concept Used

The value of a triple vector product is a linear combination of the two vectors in the parenthesis; the coefficient of each vector is the dot product of the other two; the middle vector in the triple product always has the positive sign.

03

Determine the Acceleration

Using the identity of the vector triple product:

A×B×C=BC.ACB.Aa=ωω.rrω.ωa=ωω.rrω2.

The acceleration a=ωω.rrω2

04

Determine the equation

The perpendicular vectors are given as follows,

From ωis perpendicular to r,ω.r=0

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