Chapter 3: Problem 13
Show that the center of mass is well defined, i.e., does not depend on the choice of the origin of reference for radius vectors. The momentum of a system is equal to the momentum of a particle lying at the center of mass of the system and having mass \(\sum m_{i}\). In fact, \(\left(\sum m_{i}\right) \mathbf{r}=\sum\left(m_{i} \mathbf{r}_{i}\right)\), from which it follows that \(\left(\sum m_{i}\right) \dot{\mathbf{r}}=\sum m_{i} \dot{\mathbf{r}}_{i}\). We can now formulate the theorem about momentum as a theorem about the motion of the center of mass.
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