Chapter 10: Problem 4
Many of Skellam's arguments are based directly on random-walk calculations, not derived from the continuous PDEs such as equation (1). In his original article he defines the following: \(a^{2}=\) mean square dispersion per generation, \(R=\) radial distance from point at which population was released, \(\lambda=\) growth rate of the population, \(n=\) number of elapsed generations, \(p=\) proportion of the population lying outside a circle of radius \(R\) after \(n\) generations. He proves that $$ p=\exp \frac{-R^{2}}{n a^{2}} $$ (a) If the population growth is described by $$ N_{n+1}=\lambda N_{n} $$ and initially there is just a single individual, show that the population in the \(n\)th generation is \(N_{n}=\lambda^{n}\). (b) Now consider a region that contains all but a single individual. Show that the radius of this region at the \(n\)th generation is given by $$ R_{s}=\left(n a^{2} \ln N_{*}\right)^{1 / 2} $$ [Hint: Why is it true that \(1 / N_{n}=\exp \left(-R^{2} / n a^{2}\right)\) holds for this radius?] (c) Use parts (a) and (b) to show that $$ R_{n}=n a(\ln \lambda)^{1 / 2} $$ He proves that $$ p=\exp \frac{-R^{2}}{n a^{2}} $$ (a) If the population growth is described by $$ N_{n+1}=\lambda N_{s} $$ and initially there is just a single individual, show that the population in the \(n\)th generation is \(N_{n}=\lambda^{n}\). (b) Now consider a region that contains all but a single individual. Show that the radius of this region at the \(n\)th generation is given by $$ R_{s}=\left(n a^{2} \ln N_{0}\right)^{1 / 2} $$ [Hint: Why is it true that \(1 / N_{n}=\exp \left(-R^{2} / n a^{2}\right)\) holds for this radius?] (c) Use parts (a) and (b) to show that $$ R_{n}=n a(\ln \lambda)^{1 / 2} $$ (d) Show that, save for a proportionality factor, this result agrees with the rate of spread of a population given by equation (4).
Short Answer
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Key Concepts
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