Determine when the following steady states are stable: (a) \(x_{n+1}=r x_{n}\left(1-x_{n}\right), \quad \bar{x}=0\) (b) \(x_{n+1}=-x_{n}^{2}\left(1-x_{n}\right), \quad \bar{x}=(1+\sqrt{5}) / 2\) (c) \(x_{n+1}=1 /\left(2+x_{n}\right), \quad \bar{x}=\sqrt{2}-1\) (d) \(x_{n+1}=x_{n} \ln x_{n,}^{2}, \quad \bar{x}=e^{1 / 2}\) Sketch the functions \(f(x)\) given in this problem. Use the cobwebbing method to sketch the approximate behavior of solutions to the equations from some initial starting value of \(x_{0}\). -Problems preceded by an asterisk \((\%)\) are especially challenging.

Short Answer

Expert verified
a) Stable if |r| < 1. b) Check magnitude of derivative. c) Check magnitude of derivative. d) Unstable as 3 > 1.

Step by step solution

01

Understand the Problem

Determine the stability of the given steady states for each function. For stability, we'll check if the magnitude of the derivative of the function at the steady state is less than 1.
02

Derivative Calculation for (a)

Given: \(x_{n+1} = r x_{n}(1 - x_{n}), \ \bar{x} = 0\). Calculate the derivative: \(f'(x) = \frac{d}{dx} [r x (1 - x)] = r (1 - 2x)\). Evaluate at \(\bar{x} = 0\): \(f'(0) = r\). For stability, \|f'(0)\| < 1, hence |r| < 1.
03

Derivative Calculation for (b)

Given: \(x_{n+1} = -x_{n}^2 (1 - x_{n}), \ \bar{x} = \frac{1 + \sqrt{5}}{2}\). Calculate the derivative: \(f'(x) = \frac{d}{dx} [-x^2 (1 - x)] = -2x (1 - x) + x^2 = x (x - 2) + x^2\). Evaluate at \(\bar{x} = \frac{1 + \sqrt{5}}{2}\) and check if \|f'\| < 1.
04

Derivative Calculation for (c)

Given: \(x_{n+1} = 1 / (2 + x_{n}), \ \bar{x} = \sqrt{2} - 1\). Calculate the derivative: \(f'(x) = \frac{d}{dx} \left( \frac{1}{2 + x} \right) = \frac{-1}{(2 + x)^2}\). Evaluate at \(\bar{x} = \sqrt{2} - 1\) and check if \|f'\| < 1.
05

Derivative Calculation for (d)

Given: \(x_{n+1} = x_{n} \ln (x_{n}^2), \ \bar{x} = e^{1 / 2}\). Calculate the derivative: \(f'(x) = \frac{d}{dx} [x \ln (x^2)] = \ln (x^2) + x \left( \frac{2}{x} \right) = 2 \ln (x) + 2\). Evaluate at \(\bar{x} = e^{1 / 2}\): \(f'(e^{1 / 2}) = 2 \ln (e^{1 / 2}) + 2 = 2 \cdot \frac{1}{2} + 2 = 3\). Since 3 > 1, it is unstable.
06

Cobwebbing

To sketch the functions \(f(x)\) and use cobwebbing, plot \(f(x)\) and the line \(y = x\). Then, from an initial point \(x_0\), draw a vertical line to the graph \(f(x)\), then a horizontal line to the line \(y = x\), and repeat this process to visualize the behavior of solutions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

derivative calculation
Understanding how to calculate derivatives is crucial for finding the stability of steady states. A derivative tells us how a function is changing at a particular point. It's the slope of the tangent line at a given point on the function curve. To determine stability, we'll compute the derivative of the given function at the steady state.

For example, in the case of the function given in part (a) of the exercise, we have:
Given: \(x_{n+1} = r x_{n}(1 - x_{n})\).
We need to find \(f'(x)\):
\( f'(x) = \frac{d}{dx}[r x (1 - x)] = r(1 - 2x) \).
We then evaluate this derivative at the steady state \(\bar{x} = 0\): \( f'(0) = r \). Stability is determined by checking if the absolute value of the derivative at the steady state is less than 1:
\[ |f'(\bar{x})| < 1 \]
Hence, \(|r| < 1\). This process applies similarly to parts (b), (c), and (d) with their respective functions.
cobwebbing method
The cobwebbing method is a visual tool used in analyzing the behavior of iterated functions, particularly useful for understanding difference equations. By drawing a cobweb diagram, we can see how the sequence evolves over time, giving insight into the stability of steady states.

Here’s how you use the cobwebbing method:
  • First, plot the function \(f(x)\) and the line \(y = x\).
  • Start with an initial value \(x_0\).
  • Draw a vertical line from \(x_0\) to the curve \(f(x)\).
  • From this intersection point, draw a horizontal line to the line \(y = x\).
  • Repeat the process: vertical line to the curve, horizontal line to \(y = x\).
This back-and-forth movement between the function and the line \(y = x\) will illustrate how the system behaves, converging to or diverging from a steady state.
mathematical biology
Mathematical biology uses mathematical equations and models to describe and analyze biological systems. Difference equations often model populations where generations do not overlap.

For instance, the function from part (a) of the exercise: \(x_{n+1} = r x_n (1 - x_n)\) is a well-known logistic map used in population dynamics. Here:
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Most popular questions from this chapter

Graph the function $$ f(x)=\frac{\lambda x}{1+(a x)^{b}} $$ for \(\lambda, a, b>0\) and use this to deduce the properties of the equation $$ N_{t+1}=\frac{\lambda N_{1}}{1+\left(a N_{t}\right)^{b}} $$ This is one example of a class of equations discussed by Maynard Smith (1974). What happens when \(b=1\) ?

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Consider the equation $$ N_{++1}=N, \exp \left[r\left(1-N_{1} / K\right)\right] $$ This equation is sometimes called an analog of the logistic differential equation (May, 1975). The equation models a single-species population growing in an environment that has a carrying capacity \(K\). By this we mean that the environment can only sustain a maximal population level \(N=K\). The expression $$ \lambda=\exp \left[r\left(1-N_{1} / K\right)\right] $$ reflects a density dependence in the reproductive rate. To verify this observation, consider the following steps: (a) Sketch \(\lambda\) as a function of \(N\). Show that the population continues to grow and reproduce only if \(N

Waves of disease. In a popular article that appeared in the New Scientist, Anderson and May \((1982)^{2}\) suggest a simple discrete model for the spread of disease that demonstrates how regular cycles of infection may arise in a population. Taking the average period of infection as the unit of time, they write equations for the number of disease cases \(C\), and the number of susceptible individuals \(S_{t}\) in the \(t\) th time interval. They make the following assumptions: (i) The number of new cases at time \(t+1\) is some fraction \(f\) of the product of current cases \(C_{t}\) and current susceptibles \(S_{i}\) (ii) a case lasts only for a single time period; (iii) the current number of susceptibles is increased at each time period by a fixed number, \(B(B \neq 0)\) and decreased by the number of new cases. (iv) Individuals who have recovered from the disease are immune. (a) Explain assumption (i). (b) Write the equations for \(C_{r+1}\) and \(S_{t+1}\) based on the above information. (c) Show that \(\hat{S}=1 / f, \hat{C}=B\) is a steady state of the equations. (d) Use stability analysis to show that a small deviation away from steady state may result in oscillatory behavior. (e) What happens when \(f=2 / B\) ? (f) Using a hand calculator or a simple computer program, show how solutions to the equations depict waves of incidence of the disease. Typical parameter values given by Anderson and May (1982) are \(B=12\) births per 1000 people for the U.K., or 36 births per 1000 in a third-world country. \(f=0.3 \times 10^{-4}\). Typical population data are $$ S_{0}=2000, \quad C_{0}=20 . $$

Indicate whether each of the following equations is linear or nonlinear. If linear, determine the solution; if nonlinear, find any steady states of the equation. (a) \(x_{n}=(1-\alpha) x_{0-1}+\beta x_{n}, \quad \alpha\) and \(\beta\) are constants (b) \(x_{n+1}=\frac{x_{n}}{1+x_{n}}\) (c) \(x_{n+1}=x_{n} e^{-a t_{0}}, a\) is a constant (d) \(\left(x_{n+1}-\alpha\right)^{2}=\alpha^{2}\left(x_{n}^{2}-2 x_{n}+1\right), \quad \alpha\) is a constant (e) \(x_{n+1}=\frac{K}{k_{1}+k_{2} / x_{n}}, \quad k_{1}, k_{2}\) and \(K\) are constants

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