The following predator-prey system is discussed by May (1974): $$ \begin{aligned} &\frac{d H}{d t}=r H\left(1-\frac{H}{K}\right)-\frac{k P H}{H+D} \\ &\frac{d P}{d t}=s P\left(1-\frac{P}{\gamma H}\right) \quad \text { (parasite). } \end{aligned} $$ (host), (a) Interpret the terms appearing in these equations and suggest what the various parameters might represent. (b) Sketch the \(H\) and \(P\) nullelines on an \(H P\) phase plane. (c) Apply Bendixson's criterion and Dulac's criterion (for \(B=1 / H P\) ).

Short Answer

Expert verified
The host and predator equations account for logistic growth and interaction effects. Nullclines are derived by setting derivatives to zero and sketched in the phase plane. Applying Bendixson's and Dulac's criteria involves checking divergence and modified divergence for consistent sign.

Step by step solution

01

Interpret the Host Equation

The equation for the host is \ \( \frac{dH}{dt} = rH \left(1 - \frac{H}{K} \right) - \frac{kPH}{H + D} \). Here: \ - \( rH \left(1 - \frac{H}{K} \right) \) represents the logistic growth of the host population, where \( r \) is the intrinsic growth rate and \( K \) is the carrying capacity. \ - \( \frac{kPH}{H + D} \) represents the rate at which the predator (in this case a parasite) affects the host, with \( k \) being the interaction rate between host and predator, and \( D \) being a constant that moderates the predation rate.
02

Interpret the Predator Equation

The equation for the predator (parasite) is \ \( \frac{dP}{dt} = sP \left(1 - \frac{P}{\gamma H} \right) \). Here: \ - \( sP \left(1 - \frac{P}{\gamma H} \right) \) represents the growth of the predator population, where \( s \) is the intrinsic growth rate of the predator and \( \gamma \) is a constant that scales the carrying capacity for the predator in terms of the host population.
03

Sketch Nullclines in the HP Phase Plane

Nullclines are found by setting the derivatives to zero. \ - For the host: \( \frac{dH}{dt} = 0 \Rightarrow rH \left(1 - \frac{H}{K} \right) - \frac{kPH}{H + D} = 0 \). Solve for \( P \). \ - For the predator: \( \frac{dP}{dt} = 0 \Rightarrow sP \left(1 - \frac{P}{\gamma H} \right) = 0 \). Solve for \( P \). \ Sketch these in the HP phase plane. Nullclines will be curves in this plane where the growth rates of \( H \) and \( P \) are zero.
04

Apply Bendixson's Criterion

Bendixson's criterion states that if there exists a continuously differentiable function \( D(x, y) \) such that \( \frac{\partial (P, Q)}{\partial(x, y)} = \frac{\partial P}{\partial x} + \frac{\partial Q}{\partial y} \) has a constant sign (\textgreater 0 or \textless 0), then the system has no periodic orbits in the region. Verify this by calculating the divergence of the vector field formed by the system.
05

Apply Dulac's Criterion

Dulac's criterion involves finding a function \( B \) (often called a Dulac function) such that the expression \( \frac{\partial (BP)}{\partial x} + \frac{\partial (BQ)}{\partial y} \) does not change sign in a region. For \( B = \frac{1}{HP} \), determine whether this criterion is met by evaluating the modified divergence.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Logistic Growth
Logistic growth describes how populations change over time when limited by resources such as food or space. In the equation \( \frac{dH}{dt} = rH \left(1 - \frac{H}{K} \right) \), \( r \) is the intrinsic growth rate of the host population. The term \( 1 - \frac{H}{K} \) represents the effect of carrying capacity \( K \), where \( K \) is the maximum population size that the environment can sustain. Essentially, logistic growth shows that population growth slows as the population approaches its carrying capacity. The form \( rH \left(1 - \frac{H}{K} \right) \) ensures that growth is fast when the population is small and slows down as it approaches \( K \).
Phase Plane Analysis
Phase plane analysis is a graphical tool used to study dynamical systems by plotting two variables against each other. For the predator-prey model, these variables are the host population \( H \) and the predator population \( P \). The nullclines are curves where the growth rate of either the host or the predator is zero. They are found by setting \( \frac{dH}{dt} = 0 \) and \( \frac{dP}{dt} = 0 \).

For the host equation, setting \( \frac{dH}{dt} = 0 \) gives:\[ rH \left(1 - \frac{H}{K} \right) - \frac{kPH}{H + D} = 0 \]. Solving for \( P \), we get a nullcline that describes where the host growth rate is zero. Similarly for the predator equation, setting \( \frac{dP}{dt} = 0 \) gives:\[ sP \left(1 - \frac{P}{\gamma H} \right) = 0 \]. Solving for \( P \), we obtain another nullcline where the predator growth rate is zero. By plotting these nullclines in the \( HP \) phase plane, we can see the interaction between the host and predator populations over time.
Bendixson's Criterion
Bendixson's criterion is a method used to determine whether a system of differential equations has periodic solutions, such as cycles. The criterion states that if there exists a continuously differentiable function \( D(x, y) \) such that the divergence \( \frac{\partial P}{\partial x} + \frac{\partial Q}{\partial y} \) has a constant sign (either always positive or always negative), then there are no periodic orbits within the studied region.

To apply Bendixson's criterion to our predator-prey model, calculate the divergence of the vector field formed by the system:\[ \text{div}(F) = \frac{\partial}{\partial H} \left( rH \left(1 - \frac{H}{K} \right) - \frac{kPH}{H + D} \right) + \frac{\partial}{\partial P} \left( sP \left(1 - \frac{P}{\gamma H} \right) \right) \]. If this expression has a constant sign, then Bendixson's criterion confirms that there are no periodic orbits in the phase plane.
Dulac's Criterion
Dulac's criterion is similar to Bendixson's criterion but uses a weight function \( B \) (often called a Dulac function) to modify the original system. It helps determine the non-existence of closed orbits. The criterion states that if there exists a continuously differentiable function \( B(x, y) \) such that the modified divergence expression \( \frac{\partial (B P)}{\partial x} + \frac{\partial (B Q)}{\partial y} \) does not change sign in a region, then there are no periodic orbits in that region.

For Dulac's criterion in our exercise, we choose \( B = \frac{1}{HP} \). Thus, we compute the modified divergence:\[ \frac{\partial}{\partial H} \left( \frac{1}{HP} \cdot P \right) + \frac{\partial}{\partial P} \left( \frac{1}{HP} \cdot Q \right) \]. If this expression consistently does not change sign, Dulac’s criterion indicates there are no periodic orbits in the predator-prey system.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Use Bendixson's negative criterion to show that if \(P\) is an isolated saddle point there cannot be a limit cycle in the neighborhood of \(P\) that contains only \(P\).

Show that the system $$ \frac{d x}{d t}=-2 y, \quad \frac{d y}{d t}=x-5, $$ has closed elliptical orbits. (Hint: Consider first transforming \(x\) to \(x-5\) and \(y\) to \(y / 2\) and then using a polar transformation.)

Consider the equations $$ \frac{d x}{d t}=y, \quad \frac{d y}{d t}=-x . $$ (b) By transforming variables, obtain $$ \frac{d r^{2}}{d t}=0, \quad \frac{d \theta}{d t}=-1 . $$ (b) Conclude that there are circular solutions. What is the direction of rotation? Are these cycles stable?

Lefschetz (1977) discusses the following system of equations $$ \begin{aligned} &\frac{d x}{d t}=-y+x f\left(x^{2}+y^{2}\right) \\ &\frac{d y}{d t}=x+y f\left(x^{2}+y^{2}\right) \end{aligned} $$ Show that this system is equivalent to the polar equation $$ \frac{d r}{d \theta}=r f\left(r^{2}\right) \text {. } $$

Find the polar form of the following equations and determine whether periodic trajectories exist. If so, find their stability. (a) \(\quad \frac{d x}{d t}=\frac{2 \pi y}{1+\left(x^{2}+y^{2}\right)^{1 / 2}}, \quad \frac{d y}{d t}=\frac{2 \pi x}{1+\left(x^{2}+y^{2}\right)^{1 / 2}}\). (b) $$ \begin{aligned} &\frac{d x}{d t}=y+\frac{x}{\left(x^{2}+y^{2}\right)^{1 / 2}}\left[1-\left(x^{2}+y^{2}\right)\right] \\ &\frac{d y}{d t}=-x+\frac{y}{\left(x^{2}+y^{2}\right)^{1 / 2}}\left[1-\left(x^{2}+y^{2}\right)\right] \end{aligned} $$

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free