In questions \(1-10\) solve \(\triangle \mathrm{ABC}\) given \(\mathrm{AB}=29 \mathrm{~cm}, \mathrm{BC}=41 \mathrm{~cm}, B=100^{\circ}\)

Short Answer

Expert verified
Question: In triangle ABC, given side AB = 29 cm, side BC = 41 cm, and angle B = 100°, find the remaining components: side AC, angle A, and angle C. Solution: By applying the Law of Cosines and Law of Sines, we found the following missing components of triangle ABC: - Side AC ≈ 51.15 cm - Angle A ≈ 42.49° - Angle C ≈ 37.51°

Step by step solution

01

Identify the given information

In this problem, we are given: - Side AB = 29 cm - Side BC = 41 cm - Angle B = 100° We have the task to find the remaining components of the triangle: - Angle A - Angle C - Side AC
02

Use the Law of Cosines to find side AC

First, we will use the Law of Cosines to find the third side length, AC. Using the given data, the Law of Cosines formula becomes: \[AC^2 = AB^2 + BC^2 - 2 \cdot AB \cdot BC \cdot \cos(B)\] Substitute the values given: \[AC^2 = 29^2 + 41^2 - 2 \cdot 29 \cdot 41 \cdot \cos(100^{\circ})\] Now, we can calculate the value of AC: \[AC \approx 51.15\] So side AC is approximately 51.15 cm.
03

Use the Law of Sines to find angle A

To find angle A, we can use the Law of Sines: \[\frac{\sin{A}}{AB} = \frac{\sin{B}}{BC}\] Rearrange the formula to solve for angle A: \[\sin{A} = \frac{AB \cdot \sin{B}}{BC}\] Now, substitute the given values: \[\sin{A} = \frac{29 \cdot \sin{100^{\circ}}}{41}\] Calculate the value of sin(A) and then find the measure of angle A: \[A \approx 42.49^{\circ}\] Angle A is approximately 42.49°.
04

Use the angle sum property to find angle C

Now we can find angle C using the angle sum property of triangles, which states that the sum of the three angles in a triangle is equal to 180°. Therefore: \[A + B + C = 180^{\circ}\] Substitute the values of angle A and angle B: \[42.49^{\circ} + 100^{\circ} + C = 180^{\circ}\] Now, solve for angle C: \[C \approx 37.51^{\circ}\] So angle C is approximately 37.51°.
05

Present the final solution

Now we have found all the missing components of the triangle: - Side AC ≈ 51.15 cm - Angle A ≈ 42.49° - Angle C ≈ 37.51° Thus, we have successfully solved triangle ABC.

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