Find the derivative of each of the following functions: (a) \(z(t)=\mathrm{e}^{3 t}(2 t-5)^{3}(3 t+1)^{4}\) (b) \(h(t)=3 \mathrm{e}^{-6 t} t^{7}(t+6)^{33}\) (c) \(M(p)=-p^{4} \sin ^{5} p\) (d) \(P(r)=6\left(1+r^{2}\right)^{6} \sqrt{3+r^{2}}\) (e) \(y(x)=\frac{(7-x)^{3}}{\left(3 x^{2}+1\right)^{2}}\)

Short Answer

Expert verified
with respect to \(p\): \(M'(p) = (-p^{4})' (\sin^{5} p) + (-p^{4}) (\sin^{5} p)'\) #tag_title# Step 3: Find the derivatives of individual functions #tag_content# Now, we find the derivatives of each individual function: \((-p^{4})' = -4p^{3}\) \((\sin^{5} p)' = 5\sin^{4} p (\cos p)\) #tag_title# Step 4: Substitute the derivatives back into the expression #tag_content# Replacing the derivatives in Step 2: \(M'(p) = (-4p^{3})(\sin^{5} p) + (-p^{4})(5\sin^{4} p)(\cos p)\)

Step by step solution

01

Identify individual functions

In this function, we have three individual functions multiplied together: \(\mathrm{e}^{3 t}\), \((2 t-5)^{3}\), and \((3 t+1)^{4}\).
02

Apply the product rule and chain rule

We will apply the product rule and chain rule to find the derivative of \(z(t)\) with respect to \(t\): \(z'(t) = (\mathrm{e}^{3 t})' (2 t-5)^{3} (3 t+1)^{4} + \mathrm{e}^{3 t} ((2 t-5)^{3})' (3 t+1)^{4} + \mathrm{e}^{3 t} (2 t-5)^{3} ((3 t+1)^{4})'\).
03

Find the derivatives of individual functions

Now, we find the derivatives of each individual function: \((\mathrm{e}^{3 t})' = 3\mathrm{e}^{3 t}\) \(((2 t-5)^{3})' = 3(2 t-5)^{2}(2)\) \(((3 t+1)^{4})' = 4(3 t+1)^{3}(3)\)
04

Substitute the derivatives back into the expression

Replacing the derivatives in Step 2: \(z'(t) = (3\mathrm{e}^{3 t})(2 t-5)^{3}(3 t+1)^{4} + \mathrm{e}^{3 t}(6(2 t-5)^{2})(3 t+1)^{4} +\mathrm{e}^{3 t}(2 t-5)^{3}(12(3 t+1)^{3})\) #(b) Find the derivative of \(h(t)=3 \mathrm{e}^{-6 t} t^{7}(t+6)^{33}\)#
05

Identify individual functions

In this function, we have three individual functions multiplied together: \(3\mathrm{e}^{-6 t}\), \(t^{7}\), and \((t+6)^{33}\).
06

Apply the product rule and chain rule

We will apply the product rule and chain rule to find the derivative of \(h(t)\) with respect to \(t\): \(h'(t) = (3\mathrm{e}^{-6 t})' t^{7} (t+6)^{33} + 3\mathrm{e}^{-6 t} (t^{7})' (t+6)^{33} + 3\mathrm{e}^{-6 t} t^{7} ((t+6)^{33})'\).
07

Find the derivatives of individual functions

Now, we find the derivatives of each individual function: \((3\mathrm{e}^{-6 t})' = -18\mathrm{e}^{-6 t}\) \((t^{7})' = 7t^{6}\) \(((t+6)^{33})' = 33(t+6)^{32}\)
08

Substitute the derivatives back into the expression

Replacing the derivatives in Step 2: \(h'(t) = (-18\mathrm{e}^{-6 t})t^7(t+6)^{33} + 3\mathrm{e}^{-6 t}(7t^{6})(t+6)^{33} + 3\mathrm{e}^{-6 t}t^{7}(33(t+6)^{32})\) #(c) Find the derivative of \(M(p)=-p^{4} \sin ^{5} p\)#
09

Identify individual functions

In this function, we have two individual functions multiplied together: \(-p^{4}\) and \(\sin^{5} p\).
10

Apply the product rule and chain rule

We will apply the product rule and chain rule to find the derivative of \(M(p)\).

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