By expressing the following in partial fractions evaluate the given integral. Remember to select the correct form for the partial fractions. $$ \int \frac{1}{x^{3}+x} \mathrm{~d} x $$

Short Answer

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Question: Evaluate the integral \(\int \frac{1}{x^{3}+x} \mathrm{~d} x\). Answer: The integral evaluates to \(\int \frac{1}{x^{3}+x} \mathrm{~d} x = \ln|x| + C\).

Step by step solution

01

Factor the Denominator

To factor the denominator, we can first factor out an x: $$ x^3 + x = x(x^2 + 1) $$
02

Set Up the Partial Fractions

We express the given function as a sum of partial fractions: $$ \frac{1}{x(x^2 + 1)} = \frac{A}{x} + \frac{Bx + C}{x^2 + 1} $$
03

Find A, B, and C

To find the coefficients A, B, and C, we multiply both sides by the common denominator \(x(x^2 + 1)\): $$ 1 = A(x^2 + 1) + (Bx + C)x $$ Now, let's solve for the coefficients: - Let x=0: $$ 1 = A\cdot(0+1) \Rightarrow A=1 $$ - Compare x^2 coefficients: $$ 0 = B \Rightarrow B=0 $$ - Compare constant coefficients: $$ 1 = A+C \Rightarrow C=0 $$ Thus, the partial fractions decomposition is: $$ \frac{1}{x(x^2 + 1)} = \frac{1}{x} + \frac{0x + 0}{x^2 + 1} = \frac{1}{x} $$
04

Integrate the Partial Fractions

Now we can integrate the partial fractions: $$ \int \frac{1}{x^{3}+x} \mathrm{~d} x = \int \frac{1}{x} \mathrm{~d} x $$ The integration of \(\frac{1}{x}\) is straightforward: $$ \int \frac{1}{x} \mathrm{~d} x = \ln|x| + C $$ So, the solution to the given integral is: $$ \int \frac{1}{x^{3}+x} \mathrm{~d} x = \ln|x| + C $$

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