Find \(\int \frac{2 x+7}{x^{2}+7 x} \mathrm{~d} x\).

Short Answer

Expert verified
Question: Evaluate the integral \(\int \frac{2x+7}{x^2+7x} dx\). Answer: \(\int \frac{2x+7}{x^2+7x} dx = \ln|x^2+7x| + C\), where \(C\) is an integration constant.

Step by step solution

01

Identify the substitution

Let's look at our integral, $$\int \frac{2x+7}{x^2+7x} dx.$$ Notice that if we differentiate the denominator -\(x^2 + 7x\)-, we obtain almost exactly the numerator. Specifically, $$\frac{d}{dx}(x^2+7x) = 2x + 7.$$ Thus, we will make the substitution \(u=x^2+7x\).
02

Compute du in terms of dx

Now, let's differentiate \(u\) with respect to \(x\) and isolate \(dx\). $$\frac{du}{dx} = 2x + 7.$$ So, $$du = (2x + 7)dx.$$
03

Rewrite the integral in terms of u

Now that we have the substitution and its differential, we can rewrite the integral in terms of \(u\): $$\int \frac{2x+7}{x^2+7x} dx = \int \frac{1}{u} du.$$
04

Evaluate the integral in terms of u

This new integral is straightforward to evaluate: $$\int \frac{1}{u} du = \ln|u|+C,$$ where \(C\) is an integration constant.
05

Re-substitute in terms of x

Finally, we substitute the original expression for \(u\) back into the integral: $$\ln|u|+C = \ln|x^2+7x|+C.$$
06

Simplify and write the final answer

Writing the answer more neatly, we get: $$\int \frac{2x+7}{x^2+7x} dx = \ln|x^2+7x| + C.$$

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