Find \(\int 3 \mathrm{e}^{2 x} \mathrm{~d} x\).

Short Answer

Expert verified
Answer: The integral of the function \(3e^{2x}\) is \(\frac{3}{2}e^{2x} + C\).

Step by step solution

01

Identify the constants

Within the given integral, we have the constants \(a=3\) and \(b=2\).
02

Apply the integration rule

Apply the integration rule for an exponential function multiplied by a constant: \(\int ae^{bx} dx = \frac{a}{b}e^{bx} + C\). In this case, it will be \(\int 3e^{2x} dx = \frac{3}{2}e^{2x} + C\).
03

Write down the final answer

After applying the integration rule, the final answer is: \(\int 3e^{2x} dx = \frac{3}{2}e^{2x} + C\).

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