Dynamics - Pressure in a vessel. The pressure in a vessel is \(30 \mathrm{~N} \mathrm{~cm}^{-2}\). If the pressure is reduced by \(\frac{7}{100}\) of its original value, calculate (a) the decrease in pressure, (b) the resulting pressure in the vessel.

Short Answer

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Question: The pressure in a vessel is initially 30 N/cm². If the pressure is reduced by 7%, find (a) the decrease in pressure, and (b) the resulting pressure in the vessel. Answer: (a) The decrease in pressure is 21000 N/m². (b) The resulting pressure in the vessel is 279000 N/m².

Step by step solution

01

Calculate the decrease in pressure

To find the decrease in pressure, we need to calculate \(\frac{7}{100}\) of the original pressure. First, let's convert the given pressure from \(30 N\,cm^{-2}\) to a more widely-used unit, \(N\,m^{-2}\). There are \(100 cm\) in \(1 m\), so the conversion factor is \((100)^{2}\): $$30 \mathrm{\frac{N}{cm^2} \times \frac{(100 cm)^2}{(1 m)^2}} = 300000\,\frac{N}{m^2}.$$ Now, we find the decrease in pressure: $$\mathrm{Decrease\,in\,pressure} = \frac{7}{100} \times 300000\,\frac{N}{m^2} = 21000\,\frac{N}{m^2}.$$
02

Calculate the resulting pressure

To find the resulting pressure in the vessel, subtract the decrease in pressure calculated in Step 1 from the initial pressure: $$\mathrm{Resulting\,pressure} = 300000\,\frac{N}{m^2} - 21000\,\frac{N}{m^2} = 279000\,\frac{N}{m^2}.$$ Therefore, (a) the decrease in pressure is \(21000\,\frac{N}{m^2}\), and (b) the resulting pressure in the vessel is \(279000\,\frac{N}{m^2}\).

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