Classify the following equations, specifying the order and type (linear or non-linear): (a) \(\frac{\mathrm{d}^{2} y}{\mathrm{~d} x^{2}}-\frac{\mathrm{d} y}{\mathrm{~d} x}=x^{2}\) (b) \(\frac{\mathrm{d} y}{\mathrm{~d} t}+\cos y=0\)

Short Answer

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Question: Classify the given equations in terms of order and type (linear or non-linear): (a) \(\frac{\mathrm{d}^{2} y}{\mathrm{~d} x^{2}}-\frac{\mathrm{d} y}{\mathrm{~d} x}=x^{2}\) (b) \(\frac{\mathrm{d} y}{\mathrm{~d} t}+\cos y=0\) Answer: (a) Linear second-order equation, (b) Non-linear first-order equation.

Step by step solution

01

(Classification of Equation (a))

To classify equation (a), \(\frac{\mathrm{d}^{2} y}{\mathrm{~d} x^{2}}-\frac{\mathrm{d} y}{\mathrm{~d} x}=x^{2}\), first identify the highest derivative, which in this case is the second derivative (\(\frac{\mathrm{d}^{2} y}{\mathrm{~d} x^{2}}\)). Therefore, the order of this equation is 2. Next, determine if the equation is linear or non-linear. This equation is linear since the dependent variable and its derivatives appear only to the first power and are not multiplied together. So, equation (a) is a linear second-order equation.
02

(Classification of Equation (b))

To classify equation (b), \(\frac{\mathrm{d} y}{\mathrm{~d} t}+\cos y=0\), first identify the highest derivative, which in this case is the first derivative (\(\frac{\mathrm{d} y}{\mathrm{~d} t}\)). Therefore, the order of this equation is 1. Next, determine if the equation is linear or non-linear. This equation is non-linear because of the presence of the term \(\cos y\), which makes the equation not fit the linear equation description. So, equation (b) is a non-linear first-order equation.

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