If \(z=f(x, y)=3 \mathrm{e}^{x}-2 \mathrm{e}^{y}+x^{2} y^{3}\) find \(z(1,1)\)

Short Answer

Expert verified
Answer: The value of the function at point (1,1) is \(z(1,1) = e + 1\).

Step by step solution

01

Define the function f(x, y)

The given function is: \(z = f(x, y) = 3e^x - 2e^y + x^2y^3\).
02

Substitute x = 1 and y = 1

Replace x with 1 and y with 1 in the function: \(z(1,1) = f(1,1) = 3e^1 - 2e^1 + (1^2)(1^3)\).
03

Evaluate the function

Compute the function by calculating the terms: \(z(1,1) = 3e - 2e + (1)(1) = 3e - 2e + 1\).
04

Simplify the function

Simplify the function by combining the terms: \(z(1,1) = e + 1\). So, the value of the function at point (1,1) is \(z(1,1) = e + 1\).

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