Using the temperature distribution function \(T(x, y)=\frac{\sinh \pi y \sin \pi x}{\sinh \pi}\) in Example 1.6, evaluate the temperature at the centre of the plate.

Short Answer

Expert verified
Answer: The temperature at the center of the square plate is given by the expression \(\frac{\sinh\left(\frac{\pi}{2}\right)}{\sinh(\pi)}\).

Step by step solution

01

Identify the temperature distribution function

The given temperature distribution function is: \(T(x, y) = \frac{\sinh (\pi y) \sin(\pi x)}{\sinh(\pi)}\).
02

Determine the center of the plate

Since the plate is a square with side length 1, the center of the plate will have the coordinates \((0.5, 0.5)\).
03

Substitute the coordinates of the center into the function

Now, we substitute the values of \(x = 0.5\) and \(y = 0.5\) into the temperature distribution function: \(T(0.5, 0.5) = \frac{\sinh (\pi (0.5)) \sin(\pi (0.5))}{\sinh(\pi)}\)
04

Evaluate the expression

\[T(0.5, 0.5) = \frac{\sinh\left(\frac{\pi}{2}\right) \sin\left(\frac{\pi}{2}\right)}{\sinh(\pi)}\] Using the fact that \(\sin\left(\frac{\pi}{2}\right) = 1\): \[T(0.5, 0.5) = \frac{\sinh\left(\frac{\pi}{2}\right)}{\sinh(\pi)}\]
05

Simplify the expression

The temperature at the center of the plate is given by: \[T(0.5, 0.5) = \frac{\sinh\left(\frac{\pi}{2}\right)}{\sinh(\pi)}\] This is the final expression for the temperature at the center of the plate.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.

Sign-up for free