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Chapter 3: Problem 4

Write \(0.550\) to (a) 2 s.f., (b) 1 s.f.

Short Answer

Expert verified
Question: Round the number 0.550 to (a) 2 significant figures and (b) 1 significant figure. Answer: (a) 0.550 rounded to 2 significant figures is 0.55. (b) 0.550 rounded to 1 significant figure is 0.6.

Step by step solution

01

Identify the significant figures

The number we are given is 0.550. Significant figures are all the digits from the first non-zero digit to the last non-zero digit. In this case, the significant figures are 5 and 5.
02

Round the number to 2 significant figures (a)

To round the number 0.550 to 2 significant figures, we have to find the second significant digit, which is the second 5. Since the digit to the right of the second 5 is 0, the second 5 doesn't change, and we get 0.55 as the rounded number. (a) 0.550 rounded to 2 significant figures is 0.55.
03

Round the number to 1 significant figure (b)

To round the number 0.550 to 1 significant figure, we have to find the first significant digit, which is the first 5. Since the digit to the right of the first 5 is 5 (greater than or equal to 5), the first 5 gets rounded up by 1, resulting in 6. (b) 0.550 rounded to 1 significant figure is 0.6.

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Most popular questions from this chapter

To three significant figures a number is \(3.60\). State the maximum and minimum possible values of the number.

Write each of the following as a proper fraction in its simplest form: (a) \(0.12\) (b) \(0.125\) (c) \(0.1250\) (d) \(0.85\) (e) \(0.76\)

A block of material of length \(0.9 \mathrm{~m}\) is subject to a force which causes the material to extend to a length of \(0.93 \mathrm{~m}\). Calculate the strain in the material and express it as both a proper fraction and a decimal fraction stating your answer to four decimal places.

Write each of the following as a decimal number: \(\begin{array}{lll}\text { (a) } \frac{1}{5} \text { (b) } \frac{3}{20} & \text { (c) } \frac{7}{40} & \text { (d) } \frac{21}{84} \text { (e) } \frac{110}{20}\end{array}\)

To 4 d.p. a number is \(9.9190 .\) State (a) the maximum possible value, (b) the minimum possible value of the original number.
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