Factorise (a) \(m n+11 m\), (b) \(3 p q-2 p\), (c) \(11 p q-3 q r\), (d) \(4 z x+20 y z\)

Short Answer

Expert verified
(a) \(mn + 11m\) (b) \(3pq - 2p\) (c) \(11pq - 3qr\) (d) \(4zx + 20yz\) Answer: (a) \(m(n + 11)\) (b) \(p(3q - 2)\) (c) \(q(11p - 3r)\) (d) \(4z(x + 5y)\)

Step by step solution

01

Identify the GCF of the terms in each expression

We will find the GCF of the terms in each expression to know the common factor to factorise. (a) \(mn + 11m\): The GCF is \(m\) since both terms have \(m\) as a factor. (b) \(3pq - 2p\): The GCF is \(p\) since both terms have \(p\) as a factor. (c) \(11pq - 3qr\): The GCF is \(q\) since both terms have \(q\) as a factor. (d) \(4zx + 20yz\): The GCF is \(4z\) since both terms have \(z\) as a factor and \(4\) is the largest common integer divisor.
02

Factor the GCF from each expression

Using the GCF identified in Step 1, we will factor out the common factor from each term in the expressions. (a) \(mn + 11m\): Since the GCF is \(m\), we can rewrite the expression as \(m(n + 11)\). (b) \(3pq - 2p\): Since the GCF is \(p\), we can rewrite the expression as \(p(3q - 2)\). (c) \(11pq - 3qr\): Since the GCF is \(q\), we can rewrite the expression as \(q(11p - 3r)\). (d) \(4zx + 20yz\): Since the GCF is \(4z\), we can rewrite the expression as \(4z(x + 5y)\). Now we have factorised the given expressions as follows: (a) \(mn + 11m = m(n + 11)\) (b) \(3pq - 2p = p(3q - 2)\) (c) \(11pq - 3qr = q(11p - 3r)\) (d) \(4zx + 20yz = 4z(x + 5y)\)

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