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Chapter 5: Problem 2

Remove the brackets from the given expression: \(7(2 x+y)\)

Short Answer

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Question: Remove the brackets from the given expression: \(7(2x+y)\) Answer: \(14x + 7y\)

Step by step solution

01

Identify the terms inside the brackets

In the expression \(7(2x+y)\), we have two terms inside the brackets: \(2x\) and \(y\).
02

Distribute the constant outside the brackets

Apply the distributive property to the expression: \(7(2x+y) = 7*(2x) + 7*(y)\).
03

Simplify the expression

Multiply the constant with each term: \(7*(2x) = 14x\) and \(7*(y) = 7y\). So, the simplified expression is \(14x + 7y\).

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Most popular questions from this chapter

In each case, simplify the given expression, if possible. \(7 \alpha-3 \beta+2 \gamma-7 \alpha+11 \beta\)

Remove the brackets from the given expression: \((x+1)(x-3) x\)

Find \(\frac{3}{11} \times \frac{x}{y}\)

Simplify (a) \(\frac{2}{x}-\frac{3}{2 x}\), (b) \(\frac{2}{x}+\frac{3}{2 x}\), (c) \(\frac{2}{x} \times \frac{3}{2 x}\).

Reduce each of the following fractions to its simplest form: (a) \(\frac{4}{13}\) (b) \(\frac{15}{20}\) (c) \(\frac{15}{35}\) (d) \(\frac{11}{12}\)
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