Factorise \(3 x^{3}+17 x^{2}+11 x\)

Short Answer

Expert verified
Answer: The factorization of the polynomial expression \(3x^3 + 17x^2 + 11x\) is \(x(3x^2 + 17x + 11)\).

Step by step solution

01

Identify the GCF

First, we need to find the greatest common factor of the coefficients and the variable terms. In this case, the GCF of the coefficients (3, 17, and 11) is 1, and the GCF of the variable terms (\(x^3\), \(x^2\), and \(x\)) is \(x\). So, the overall GCF is \(1x\).
02

Factor out the GCF

Next, we will factor out the GCF (\(1x\)) from each term in the given expression. \(3x^3 + 17x^2 + 11x = x(3x^2 + 17x + 11)\)
03

Factor the quadratic expression

Now, we need to factorise the quadratic expression inside the parenthesis (\(3x^2 + 17x + 11\)). To do this, we need to find two binomials whose product gives the quadratic expression. In this case, there are no such binomials as the expression is prime. Thus, we have reached the final factorisation.
04

Write the final factorization

Since we were not able to factorise the quadratic expression further, we can now write the final factorisation of the given expression: \(3x^3 + 17x^2 + 11x = x(3x^2 + 17x + 11)\)

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