Chapter 7: Problem 4
Solve the simultaneous equations $$ 3 x-2 y=11,5 x+7 y=39 $$
Chapter 7: Problem 4
Solve the simultaneous equations $$ 3 x-2 y=11,5 x+7 y=39 $$
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Get started for freeVerify that the given value is a solution of the given equation. $$ 11 x-1=10, x=1 $$
Express in partial fractions \(\frac{x^{3}+x+1}{x^{2}+7 x+12}\).
Solve the inequality \(|3 x+2| \leq 4\)
For each fraction state the degrees of the numerator and denominator, and hence determine which are proper and which are improper: (a) \(\frac{x+1}{x}\) (b) \(\frac{x^{2}}{x^{3}-x}\) (c) \(\frac{(x-1)(x-2)(x-3)}{x-5}\)
In each case verify that the given values satisfy (b) \(x=4, y=3\) satisfy \(x+y=7\) and the given simultaneous equations: (a) \(x=2, y=-2\) satisfy \(7 x+y=12\) and (c) \(x=-3, y=2\) satisfy \(8 x-y=-26\) \(-3 x-y=-4\) and \(9 x+2 y=-23\)
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