Under what circumstances is angular momentum constant? Give an example of a situation in which the x component of angular momentum is constant, but the y component isn’t.

Short Answer

Expert verified

The x component of the angular momentum is zero.

Step by step solution

01

Definition of Angular Momentum

The rotating inertia of an object or system of objects in motion about an axis that may or may not pass through the object or system is described by angular momentum.

02

Derivation of Angular Momentum

The net torque (τ) exerted to a particle about a given place equals the rate of change of its angular momentum at that location.

It is given by formula:

τ=dLdt …… (1)

If the external torque is not applied,τ=0,

Then equation (1), is written as

dLdt=0dL=0Lf=Li

Final angular momentum Lfis equal to the initial angular momentum LiL

Constant

If the net torque acting on the particle is zero, the total angular momentum of the rotating object remains constant.

03

Step 3: The situation in which the x component of angular momentum is constant is-

This is fixed at one end and moves in a plane of the paper when a ball moves in a circular manner. There will be a torque acting in the vertical direction due to gravitational and centripetal force.

As a result, the angular momentum component does not remain constant. The direction isn't affected by any horizontal torque. As a result, the angular momentum component has no value.

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Most popular questions from this chapter

A device consists of eight balls, each of massattached to the ends of low-mass spokes of length L so the radius of rotation of ball is L/2. The device is mounted in the vertical plane, as shown in Figure 11.73. The axle is help up by supports that are not shown, and the wheel is free to rotate on the nearly frictionless axle. A lump of clay with massm falls and sticks to one of the balls at the location shown, when the spoke attached to that ball is 45°to the horizontal. Just before the impact the clay has a speed v, and the wheel is rotating counter clock wise with angular speedω .

(a.) Which of the following statements are true about the device and the clay, for angular momentum relative to the axle of the device? (1) the angular momentum of the device + clay just after the collision is equal to the angular momentum of the device +clay just before the collision. (2) The angular momentum of the falling clay is zero because the clay is moving in a straight line. (3) Just before the collision, the angular momentum of the wheel is 0. (4) The angular momentum of the device is the sum of the angular momenta of all eight balls. (5) The angular momentum of the device is the same before and after the collision. (b) Just before the impact, what is the (vector) angular momentum of the combined system of device plus clay about the center C? (As usual, xis to the right, yis up, and zis out of the screen, toward you) (c) Just after the impact, what is the angular momentum of the combined system of device plus clay about the center C? (d) Just after the impact, what is the (vector) angular velocity of the device? (e) Qualitatively. What happens to the total linear momentum is changed system? Why? (1) some of the linear momentum is changed into energy. (2) some of the linear momentum is changed into angular momentum. (3) There is no change because linear momentum is always conserved. (4) The downward linear momentum decreases because the axle exerts an upwards force. (f) qualitatively, what happens to the total kinetic energy of the combined system? Why? (1) some of the kinetic energy is changed into linear momentum. (2) some of the kinetic energy is changed into angular momentum. (3) The total kinetic energy decreases because there is an increase of internal energy in this inelastic collision. (4) There is no change because kinetic energy is always conserved.

Evaluate the cross product which \(\left( {5\widehat I + 3\widehat J} \right) \times \left( { - 4\widehat I + 2\widehat J} \right),\)expands to\( - 20\widehat I \times \widehat I + 10\widehat I \times \widehat J - 12\widehat J \times \widehat I + 6\widehat J \times \widehat J\).

What is the angular momentum \({\overrightarrow L _A}\)If \({\overrightarrow r _A} = (9, - 9,0)\)m and \(\overrightarrow p = (12,10,0)\)\(kg.m/s?\)

If an object has a moment of inertia \(19\,\,{\rm{kg}} \cdot {{\rm{m}}^{\rm{2}}}\) and the magnitude of its rotational angular momentum is \(36\,\,\,{\rm{kg}} \cdot {{\rm{m}}^{\rm{2}}}{\rm{/s}},\) what is its rotational kinetic energy?

A sick of length Land mass Mhangs from a low-friction axle (Figure 11.90). A bullet of mass mtravelling at a high speedstrikes vnear the bottom of the stick and quickly buries itself in the stick.

(a) During the brief impact, is the linear momentum of the stick + bullet system constant? Explain why or why not. Include in your explanation a sketch of how the stick shifts on the axle during the impact. (b) During the brief impact, around what point does the angular momentum of the stick + bullet system remain constant? (c) Just after the impact, what is the angular speed ωof the stick (with the bullet embedded in it) ? (Note that the center of mass of the stick has a speed ωL/2.The moment of inertia of a uniform rod about its center of mass is112ML2.(d) Calculate the change in kinetic energy from just before to just after the impact. Where has this energy gone? (e) The stick (with the bullet embedded in it) swings through a maximum angleθmaxafter the impact, then swing back. Calculate θmax.

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