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Chapter 19: Q1Q (page 794)

How is the initial current through a bulb affected by putting a capacitor in series in the circuit? Explain briefly.

Short Answer

Expert verified

In the presence of a capacitor, the direct current, flowing in the circuit, starts reducing and becomes zero after a certain time interval.

Step by step solution

01

Parallel Plate Capacitor

When two conducting plates are placed parallel to each other, with a layer of insulating material between them, the combination is called a parallel plate capacitor. It has the ability to store energy in the form of an electric field, between the plates.

02

Explanation

When a capacitor is connected to a d.c. source, the charge starts accumulating at the plates. Due to this accumulation of charge, an electric field is developed between the plates, such that it opposes the flow of current through the circuit.

With more and more charge accumulation, the strength of the electric field between the plates also increases. Thus, it will more strongly oppose the current. So, the current in the circuit will be reduced.

03

Conclusion

When a capacitor is connected to a d.c. source, the current in the circuit starts reducing and becomes zero after a certain time interval.

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Most popular questions from this chapter

The capacitor in Figure 19.65 is initially charged, then the circuit is connected. Which graph in Figure 19.66 best describes the current through the bulb as a function of time?

In the circuit shown in Figure 19.77 the emf of the battery is 7.4V. Resistor R1has a resistance of 31Ω, resistor R2 has a resistance of 47Ω, and resistor R3has a resistance of 52Ω . A steady current flows through the circuit.

(a)What is the equivalent resistance of R1and R2 ? (b) What is the equivalent resistance of all three resistors? (c) What is the conventional current throughR3

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