The capacitor in Figure 19.67 is initially uncharged, then the circuit is connected. Which graph in Figure 19.66 best describes the current through the bulb as a function of time?

Short Answer

Expert verified

Figure (d) best depicts the current in the circuit.

Step by step solution

01

Given data

An uncharged capacitor is connected to a bulb and two batteries in series.

02

Charging of a capacitor

When an uncharged capacitor is connected to a battery, positive charges from the positive end of the battery flow to one plate of the capacitor and start accumulating there and negative charges from the negative end of the battery move to the other plate of the capacitor and start accumulating there.

03

Determination of the graph of the current in the circuit

As charges accumulate on the plates of the capacitor, a fringe field is developed in the circuit which opposes the field from the battery. As charge concentration increases on the plates, so does the fringe field. The net field in the circuit decreases which decreases the current. This continues until the fringe field completely cancels out the field from the battery and current in the circuit is zero. This is best depicted by figure (d).

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Most popular questions from this chapter

A circuit consists of two batteries (with negligible resistance), six ohmic resistors and connecting wires that have negligible resistance. The resistance R1is 10Ω, R2 is 20Ω, R3 is 30Ω, R4is 12Ω, R5is 15Ω and R6 is 20Ω. Unknown currents I1,I2 ,I3 ,I4 , I5 and I6 have their directions marked on the circuit diagram in figure 19.87.

(a) Write down a set of equations that could be solved for the six unknown currents. Make sure you can explain how to you got these equations. (b) When a correct set of equations is solved the currents are as follows (to the nearest miiampeares) I1=0.4394A, I2=0.3312A, I3=0.0065A, I4=0.1082A, I5=0.3247Aand I6=0.4329A. Check your equations by substituting in these numbers. (c) Suppose that you connect the negative lead of a voltmeter to location C. What does the voltmeter read, including both magnitude and sign? (d) What does the power output of the 5 V battery? (e) Resistor is made of a very thin metal wire that is 3 mm long, with a diameter of 0.1 mm. What is the electric field inside the metal resistor.

A battery with negligible internal resistance is connected to a resistor. The power produced in the battery and power dissipated in the resistor are both P1. Another resistor of same kind is added, so circuit consists of a battery and two resistors in series. (a) in terms of P1 how much power is dissipated in the first resistor ? . (a) in terms of P1 how much power is produced in the battery ? (c ) The circuit is rearranged so that the two resistors are in parallel rather than in series. In terms of P1, now how much power is produced in the battery?

State whether the following statement is true or false, and briefly explain why: “In the two circuits shown in Figure 19.64, the battery output power is greater in circuit 2 because there is an additional resistor dissipating power.”

A certain has rectangular plates56cmby 24 cm and the gap width is 20.0 mm. What is its capacitance? We see that typical capacitances are very small when measured in farads. A role="math" localid="1662139654139" 1Fcapacitor is quite extraordinary. Apparently it has a very large area A(all wrapped up in a small package), and a vary small gap s.

Work and energy with a capacitor: A capacitor with capacitance Chas an amount of charge q on one of its plates, in which case the potential difference across the plates is ΔV=q/C (definition of capacitance). The work done to add a small amount of charge dq when charge the capacitor is dqΔV=dqq/C. Show by integration that the amount of work required to charge up the capacitor from no charge to final charge Q is 12(Q2/C). Since this is the amount of work required to charge the capacitor, it is also the amount of energy stored in the capacitor. Substituting Q=CΔV, we can also express the energy as 12CΔV2.

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