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Chapter 19: Q50P (page 799)

When a single thin-filament bulb is connected to a 1.5Vbattery, the current through the battery is about80mAIf you add another thin-filament bulb in parallel, the battery current of course increase to160mA. Is the battery ohmic? That is, is the current through the battery proportional to the potential difference across the battery?

Short Answer

Expert verified

No

Step by step solution

01

Given Data

VoltageV=1.5VCurrentI1=80mAI2=160mA

02

Concept

Generally, the current is proportional to the difference of electric potential. The current is inversely proportional to the resistance.

03

Find the battery is ohmic

  • The battery is not ohmic.
  • The current is not proportional to voltage.
  • If you double the current through a battery, the battery voltage hardly changes at all.
  • The battery voltage certainly does not double and will actually decrease slightly.
  • The battery voltage is not proportional to the current.

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Most popular questions from this chapter

In the circuit shown in Figure 19.77 the emf of the battery is 7.4V. Resistor R1has a resistance of 31Ω, resistor R2 has a resistance of 47Ω, and resistor R3has a resistance of 52Ω . A steady current flows through the circuit.

(a)What is the equivalent resistance of R1and R2 ? (b) What is the equivalent resistance of all three resistors? (c) What is the conventional current throughR3

In the circuit shown in Figure 19.77 the emf of the battery is 7.4V. Resistor R1has a resistance of 31Ω, resistor R2 has a resistance of 47Ω, and resistor R3has a resistance of 52Ω . A steady current flows through the circuit.

(a)What is the equivalent resistance of R1and R2 ? (b) What is the equivalent resistance of all three resistors? (c) What is the conventional current throughR3

Why can birds perch on the bare wire of a power line without being electrocuted?

You are marooned on a desert island full of all kinds of standard electrical apparatus including a sensitive voltmeter, but you don’t have an ammeter. Explain how you could use the voltmeter to measure currents.

A circuit consists of a battery, whose emf is K, and five Nichrome wires, three thick and two thin as shown in Figure 19.78. The thicknesses of the wires have been exaggerated in order to give you room to draw inside the wires. The internal resistance of the battery is negligible compared to the resistance of the wires. The voltmeter is not attached until part (e) of the problem. (a) Draw and label appropriately the electric field at the locations marked × inside the wires, paying attention to appropriate relative magnitudes of the vectors that you draw. (b) Show the approximate distribution of charges for this circuit. Make the important aspects of the charge distribution very clear in your drawing, supplementing your diagram if necessary with very brief written descriptions on the diagram. Make sure that parts (a) and (b) of this problem are consistent with each other. (c) Assume that you know the mobile-electron density n and the electron mobility u at room temperature for Nichrome. The lengths (L1,L2,L3)and diameters (d1,d2)of the wires are given on the diagram. Calculate accurately the number of electrons that leave the negative end of the battery every second. Assume that no part of the circuit gets very hot. Express your result in terms of the given quantities (K,L1,L2,L3,d1,d2,nandu) . Explain your work and identify the principles you are using. (d) In the case that d2≪d1, what is the approximate number of electrons that leave the negative end of every second? (e) A voltmeter is attached to the circuit with its + lead connected to location B (halfway along the leftmost thick wire) and its - lead connected to location C (halfway along the leftmost thin wire). In the case thatd2≪d1 , what is the approximate voltage shown on the voltmeter, including sign? Express your result in terms of the given quantities (K,L1,L2,L3,d1,d2,nandu).
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