Suppose that you charge a 1 F capacitor in a circuit containing two 15Vbatteries, so the final potential difference across the plates is3V.How much charge is on each plate? How many excess electrons are on the negative plate?

Short Answer

Expert verified

(i) 3 C (ii)1.9×1019electrons

Step by step solution

01

Given Data

Capacitance, C = 1F

The final potential difference is 3 V

02

Concept

The ratio of the charge and the potential difference is known as the capacitance.

03

Step 3(i): Determine the charge

The charge on each plate,

Q=C×V=1×3=3C

Hence, the charge on each plate is 3 C

04

Step 4(ii): Determine the number of electrons

The number of electrons,

N=Qe=31.6×10-19=1.9×1019electrons

Hence, the number of electrons is 1.9×1019electrons

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A circuit consists of two batteries (with negligible internal resistance), five ohmic resistors (Figure 19.88). The connecting wires that have negligible resistance. The letters A through are shown to make it possible to refer to specific parts of the circuit.

(a) Write all the equations necessary to solve for the unknown currents I1, I2, I3, I4 and I5, whose directions are indicated on the circuit diagram. Do not solve the equations but do explain very clearly what your equations are based on and to what they refer.

Assume that a computer program has solved your equations in terms of known battery voltages and known resistances so that the currents I1, I2,I3 ,I4and I5are are known. (b) In terms of known quantities calculate VD-VAand check that your sign makes sense. (c) In terms of known quantities, calculate the power produced in battery number 2.

The two circuits shown in Figure 19.59 have different capacitors but the same batteries and thin-filament bulbs. The capacitors in circuit 1and circuit 2areidentical exceptthat the capacitor in circuit 2was constructed with its plates closer together. Both capacitors have air between their plates. The capacitors are initially uncharged. In each circuit the batteries are connected for a short time compared to the time required to reach equilibrium, and then they are disconnected. In which circuit (1or 2) does the capacitor now have more charge? Explain your reasoning in detail.

State whether the following statement is true or false, and briefly explain why: “In the two circuits shown in Figure 19.64, the battery output power is greater in circuit 2 because there is an additional resistor dissipating power.”

The deflection plates in an oscilloscope are 10cm by 2cm with a gap distance of 1mm. A 100V potential difference is suddenly applied to the initially uncharged plates through a 1000Ωresistor in series with the deflection plates. How long does it take for the potential difference between the deflection plates to reach 95V?

Consider a copper wire with a cross-sectional area of 1 mm2 (similar to your connecting wires ) and carrying 0.3 A of current, which is about what you get in a circuit with a thick-filament bulb and two batteries in series. Calculate the strength of the very small electric field required to drive this current through the wire.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free