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Chapter 19: Q56P-b (page 799)

In the circuit shown in Figure 19.77 the emf of the battery is 7.4V. Resistor R1has a resistance of 31Ω, resistor R2 has a resistance of 47Ω, and resistor R3has a resistance of 52Ω . A steady current flows through the circuit.

(a)What is the equivalent resistance of R1and R2 ? (b) What is the equivalent resistance of all three resistors? (c) What is the conventional current throughR3

Short Answer

Expert verified

70.68Ω

Step by step solution

01

Given Data

R1=31ΩR2=47ΩR3=52Ωemf=7.4V

02

Concept

The equivalent resistance is the addition of the resistances, when the batteries are connected in series.

03

Step 3(b): Determine the equivalent resistance of all three resistors

The equivalent resistance of all the three resistors,

R=R3+R4=52+18.68=70.68ΩReferring to subpartaof the SID:875865 - 19 - 56P - a,takeR4value

Hence, the equivalent resistance of all three resistors is 70.68Ω

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Most popular questions from this chapter

The conductivity of tungsten at room temperature,1.8×107A/m2/V/m , is significantly smaller than that of copper. At the very high temperature of a glowing light-bulb filament (nearly 3000 kelvins), the conductivity of tungsten is 18 times smaller than it is at room temperature. The tungsten filament of a thick-filament bulb has a radius of about 0.015 mm. Calculate the electric field required to drive 0.20 A of current through the glowing bulb and show that it is very large compared to the field in the connecting copper wires.

A capacitor with a slab of glass between the plates is connected to a battery by Nichrome wires and allowed to charge completely. Then the slab of glass is removed. Describe and explain what happens. Include diagrams. If you give a direction for a current, state whether you are describing electron current or conventional current.

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