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Chapter 19: Q76P (page 802)

The deflection plates in an oscilloscope are 10cm by 2cm with a gap distance of 1mm. A 100V potential difference is suddenly applied to the initially uncharged plates through a 1000 Ωresistor in series with the deflection plates. How long does it take for the potential difference between the deflection plates to reach 95V?

Short Answer

Expert verified

t=5.3×10-8s

Step by step solution

01

Given data

Plate area A=10 cm×2 cm

Gap s=1 mm

Potential difference V=95 V

Max. Potential difference Vmax=100 V

Resistance R=1000 Ω

02

Formula used

V=Vmax(1-exp-tRC)

Where,Vmaxis max. Potential difference reaches

t Is time require

R is resistance andC is the capacitance

03

Calculation for time required

C=ε0As=8.85×10-12×2×10-31×10-3=1.77×10-11 F

V=Vmax1-exp-tRC95=1001-exp-t1000×1.77×10-110.95=1-exp-t1.77×10-8exp-t1.77×10-8=0.05

t=5.3×10-8s

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Most popular questions from this chapter

The capacitor in Figure 19.67 is initially uncharged, then the circuit is connected. Which graph in Figure 19.66 best describes the current through the bulb as a function of time?

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