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Chapter 4: 9 CP (page 156)

Question:A certain metal with atomic mass 2 × 10−25 kg has an interatomic bond with length 2.1 × 10−10 m and stiffness 40 N/m. What is the speed of sound in a rod made of this metal?

Short Answer

Expert verified

V=3500m/s

Step by step solution

01

Given Information

Atomic mass =2×10-25kg

Length= 2.1×10-10m

Stiffness=40N/m

02

Formula speed of sound in a rod

V=dKsm

Where,

d=length

ks= stiffness

m=mass

03

calculation of speed of sound in a rod

V=dKsm

V=2.1×10-10402.0×10-25V=2969.848ms

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Most popular questions from this chapter

Here on Earth you hang a mass from a vertical spring and start it oscillating with amplitude1.7cm. You observe that it takes 2.1sto make one round-trip. You construct another vertical oscillator with a mass 6 times as heavy and a spring 10 times as stiff. You take it to a planet wheregplanet=6.8N/kg.You start oscillating with amplitude3.3cm. How long does it take for the mass to make one round-trip?

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