Bob is pushing a box across the floor at a constant speed of , applying a horizontal force whose magnitude is20N . Alice is pushing an identical box across the floor at a constant speed of 2m/s, applying a horizontal force. (a) What is the magnitude of the force that Alice is applying to the box? (b) With the two boxes starting from rest, explain qualitatively what Alice and Bob did to get their boxes moving at different constant speeds.

Short Answer

Expert verified

a) The force that Alice is exerting on the box is .

b) Alice and Bob initially applied force is large than the static friction, so the box starts moving; when the desired speed is reached, the force is reduced, resulting in a net force of zero.

Step by step solution

01

Identification of given data

  • Bob is pushing the box with constant speed,vb=1m/s
  • Alice is pushing the box with constant speed,va=2m/s
  • Bob applying horizontal force,Fb=20N
02

Significance of Newton’s 2nd law of motion

Newton’s 2nd law of motion is, the formula F = ma is crucial because it depicts the connection between forces and motion. It enables you to compute an object's acceleration (and hence velocity and direction) using known forces.

This is extremely useful for scientists, engineers, inventors, and other professionals. We can map out an object's trajectory by regulating, measuring, or estimating the force exerted on it and so know where it will be at any given moment.

03

Calculating the force is applied to the box

Part a)

By applying Newton's 2nd Law of motion,

F=ma

Where is force is applied, is the mass of the box, is the acceleration of the box.

Here constant speed, which means acceleration is zero.

Fa-Fb=0Fa=FbFa=20N

Thus, the force that Alice is exerting on the box is .

04

Condition for constant speed

Part b)

Alice applied a larger force at first to accelerate the box that required some speed, then gradually decreased the external force to keep the speed constant.

Thus,Alice and Bob initially applied force is large than the static friction, so the box starts moving; when the desired speed is reached, the force is reduced, resulting in a net force of zero.

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Most popular questions from this chapter

Young’s modulus for aluminium is .The density of aluminium is ,and the mass of one mole is 27g. If we model the interactions of neighbouring aluminium atoms as though they were connected by spring, determine the approximate spring constant of such a spring. Repeat this analysis for lead is: Young’s modulus for Lead and the density of lead is , and the mass of one mole is 207g. Make a note of these results, which we will use for various purposes later on. Note that aluminium is a rather stiff material, whereas lead is quite soft.

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It was found that a 20gmass hanging from a particular spring had an oscillation period of 1.2s. (a) When two 20gmasses are hung from this spring, what would you predict for the period in seconds? Explain briefly.


Figure 4.58

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For this problem you will need measurements of the position vs. time of a block sliding on a table, starting with some initial velocity, showing down, and coming to rest. If you do not have an appropriate laboratory setup for making these measurements, your instructor will provide you with such data. Analyze these data to determine the coefficient of friction and to see how well they support the assertion that the force of sliding friction is essentially independent of the speed of sliding.

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