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Chapter 4: Q46P (page 167)

You drag a block across a table while a friend presses down on the block. The coefficient of friction between the table and the block is 0.6. The vertical component of the force exerted by the table on the block is 190N. How big is the horizontal component of the force exerted by the table on the block?

Short Answer

Expert verified

The horizontal component of the force is 114N.

Step by step solution

01

Identification of the given data

The coefficient of friction between the table and the block isµ=0.6

The vertical component of the force exerted by the table on the block isN=190N

02

Determination of the horizontal component of the force exerted by the table on the block

Force,

F=μN=0.6×190=114N

Hence the horizontal component of the force exerted by the table on the block is 114N.

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Most popular questions from this chapter

A chain of length L, and mass M is suspended vertically by one end with the bottom end just above a table. The chain is released and falls, and the links do not rebound off the table, but they spread out so that the top link falls very nearly the full distance L. Just before the instant when the entire chain has fallen onto the table, how much force does the table exert on the chain? Assume that the chain links have negligible interaction with each other as the chain drops, and make the approximation that there is very large number of links. Hint: Consider the instantaneous rate of change momentum of the chain as the last link hits the table.

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For this problem you will need measurements of the position vs. time of a block sliding on a table, starting with some initial velocity, showing down, and coming to rest. If you do not have an appropriate laboratory setup for making these measurements, your instructor will provide you with such data. Analyze these data to determine the coefficient of friction and to see how well they support the assertion that the force of sliding friction is essentially independent of the speed of sliding.

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