The radius of a merry-go round is 11m, and it takes 12s to go around one. What is the speed of an atom in the outer rim?

Short Answer

Expert verified

The speed of an atom in the outer rim is 5.76m/s.

Step by step solution

01

Given information

Radius of merry go round is R=11m

Time to complete one round is t=12s.

02

Formula used

We are asked to determine the speed of an atom in the outer rim. The speed is the change in the distance with time. So, it is given by

v=dt …… (1)

03

The speed is the change in the distance with time

When the atom travel through one round, it moves above the circumference of the circle. The circumference is given by,

2πR

Where, Ris the radius of the circle. So, the distance where the atom travel is,

d=2πR

Plug the expression for dinto equation (1) to get the new form,

V=2πRt …… (2)

Now plug our values for Randt into equation (2) to get the speed of the atom in the outer rim,

v=2πRt=2π11m12s=5.76m/s

Therefore, the speed of an atom in the outer rim is 5.76m/s.

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