In a table like the one shown, write an inequality comparing each quantity in the steady state for a narrow resistor and thick connecting wires, which are made of the same material as the resistor.

Electron current in resistor

<,=, or >

Electron current in Thick Wires

nR

nw

AR

Aw

uR

uw

ER

Ew

vR

vw

Short Answer

Expert verified

Electron current in resistor

<,=, or >

Electron current in Thick Wires

nR

=

nw

AR

<

Aw

uR

=

uw

ER

>

Ew

vR

>

vw

Step by step solution

01

Given data

A narrow resistor is connected in a circuit using thick connecting wires

02

Current in a circuit and drift velocity

Current in a wire of charge density , cross sectional area and drift velocity is given by:

I=neAv............(1)

Here, is the charge of an electron.

The drift velocity v as a function of the mobility u and the electric field E isV=uE............(2)

03

Comparison between quantities

The current in the circuit is the same everywhere in steady state. The electron density n and the mobility u are inherent properties of any material. Since the resistor and the wire are made of the same material, they have the same electron density and mobility, that isnR=nwuR=uw

The resistor is thin and the wire is thick. Thus the cross sectional area of the wire is greater than that of the resistor, that isAw>AR

Since cross sectional area of the wire is greater than that of the resistor, and current is same in both, from equation (1):

vR>vw

Thus, from equation (2):

ER>Ew

The comparison in quantities can be summarized as

Electron current in resistor

<,=, or >

Electron current in Thick Wires

nR

=

nw

AR

<

Aw

uR

=

uw

ER

>

Ew

vR

>

vw

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Most popular questions from this chapter

In a circuit with one battery, connecting wires, and a 12cmlength of Nichrome wire, a compass deflection of 6°is observed. What compass deflection would you expect in a circuit containing two batteries in a series, connecting wires and a36cm length of thicker Nichrome wire (double the cross-sectional area of the thin piece)? Explain.

Suppose that a wire leads into another, thinner wire of the same material that has only a third the cross-sectional area. In the steady state, the number of electrons per second flowing through the thick wire must be equal to the number of electrons per second flowing through the thin wire. If the drift speedV1¯in the thick wire is 4×10-5ms, what is the drift speed V¯2in the thinner wire?

What would be the potential difference VC-VBacross the thin resistor in Figure 18.103 if the battery emf is3.5V ? Assume that the electric field in the thick wires is very small (so that the potential differences along the thick wires are negligible). Do you have enough information to determine the current in the circuit?

Why does the brightness of a bulb not change noticeably when you use longer copper wires to connect it to the battery? (1) Very little energy is dissipated in the thick connecting wires. (2) The electric field in connecting wires is very small, so emfEbulbLbulb. (3) Electric field in the connecting wires is zero, so emfEbulbLbulb. (4) Current in the connecting wires is smaller than current in the bulb. (5) All the current is used up in the bulb, so the connecting wires don’t matter.

During the initial transient leading to the steady state, the electron current going into a bulb may be greater than the electron current leaving the bulb. Explain why and how these two currents come to be equal in the steady state.

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