Consider setting up an integral to find an algebraic expression for the electric field of a uniformly charged rod of length L , at a location on the midplane. If we choose an origin at the center of the rod, what are the limits of integration?

Short Answer

Expert verified

The limits of the integration will be -L/2to+L/2.

Step by step solution

01

Given data

A uniformly charged rod of length L.

02

Step 2:Integration to find the electric field

The net electric field due to a uniform charge distribution is obtained by first calculating the electric field due to a small charge element in the distribution and then integrating it over the whole distribution.

03

Step 3:Determining the integration limit to find the electric field due to a uniformly charged rod on its midplane

To obtain the field due to the rod on its midplane, at first, the field due to a small length elementdx with a chargeλdx whereλis the charge per unit length is obtained. Here thexaxis is chosen along the rod with the mid-point at the origin.

Thus the integration to find the electric field due to the whole rod will be carried out fromrole="math" localid="1668498796461" -L/2 to +L/2.

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Most popular questions from this chapter

For a disk of radius 20 cm with uniformly distributed charge 7×10-6C, calculate the magnitude of the electric field on the axis of the disk, 5 mm from the center of the disk, using each of the following equations:

(a)E=(Q/A)2ε0[1-zR2+z21/2]

(b)EQ/A2ε0[1-zR]

(c)EQ/A2ε0

(d) How good are the approximate equations at this distance? (e) At what distance does the least accurate approximation for the electric field give a result that is closest to the most accurate: at a distance R/2, close to the disk, at a distance R, or far from the disk?

What is wrong with Figure 15.35 and this associated incorrect student explanation? “The electric field at location inside the uniformly charged sphere points in the direction shown, because the charges closest to this location have the largest effect.” (Spheres provide the most common exception to the normally useful rule that the nearest charges usually make the largest contribution to the electric field.)

Coulomb’s law says that electric field falls off like 1/z2. How can Efor a uniformly charged disk depend on [1-z/R], or be independent of distance?

Question: A solid spherical plastic ball was rubbed with wool in such a way that it acquired a uniform negative charge all over the surface. Make a sketch showing the polarization of molecules inside the plastic ball, and explain briefly.

For a disk of radius R=20cm and Q=6×10-6C, calculate the electric field 2 mm from the center of the disk using all three equations:

role="math" localid="1656928965291" E=(Q/A)2ε0[1-z(R2+z)1/2]

EQ/A2e0[1-zR],andEQ/A2e0

How good are the approximate equations at this distance? For the same disk, calculate E at a distance of 5 cm (50 mm) using all three equations. How good are the approximate equations at this distance?

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