Can you charge a piece of plastic by induction? Explain, using diagram. Compare with the amount of charging obtained when you charge a piece of metal by induction.

Short Answer

Expert verified

The piece of plastic would not be charged by the induction process.

The amount of charging by the induction method for a piece of metal is more than charging a piece of plastic.

Step by step solution

01

Understanding the charging by induction

In this problem, the concept of charging a plastic piece with the help of the induction phenomenon is discussed. This type of charging occurs without any physical contact between a charged object and an uncharged object.

02

Analysis of whether a piece of plastic can be charged by induction or not

A piece of plastic comes under the category of insulating material and insulators are not able to move/flow electric charge through it. So the piece of plastic generally cannot be charged by the induction method.

A schematic of charging a metallic conductor piece by induction method is represented below.

Here, A is the metal sphere and B is the plastic rod. And E and F denote the locations of negative and positive charges.

Let us consider a neutral metal sphere and a negatively charged plastic rod. From the above figure, if the negatively charged plastic rod comes closure to the neutral sphere, then separation of charge takes place/ occurs.

The positive charges in the sphere get attracted towards the plastic rod and move to one end of the sphere that is closer to the plastic rod.

Thus, the piece of plastic would not be charged by the induction process.

03

Comparison of the amount of charging obtained when charging a piece of metal comparison to a piece of plastic by induction

The charging process of a type of neutral object/ piece by bringing closure to another type of charged object without any direct contact refers to induction charging. To understand the charging of a piece of plastic or a piece of metal, the nature of the conductor and polarization process is important.

As a piece of plastic is an insulator, whereas a piece of metal is a conductor, the amount of charging obtained by induction for a piece of metal is more than the amount of charging of a piece of plastic by the induction process.

Thus, the amount of charging by the induction method for a piece of metal is more than charging a piece of plastic.

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Most popular questions from this chapter

An electric field of magnitude 190N/C is applied to a solution containing chloride ions. The mobility of chloride ions in solution is 7.91×10-8(m/s)/(N/C).What is the average drift speed of the chloride ions in the solution?

You rub a clear plastic pen with wool, and observe that a strip of invisible tape is attracted to the pen. Assuming that the pen has a net negative charge, which of the following could be true? Select all that apply. (1) The tape might be negatively charged. (2) The tape might be positively charged. (3) The tape might be uncharged. (4) There is not enough information to conclude anything.

A student said, “When you touch a charged piece of metal, the metal is no longer charged: all the charge on the metal is neutralized.” As a practical matter, this is nearly correct, but it Isn’t exactly right. What’s wrong with saying that all the charge on the metal is neutralized?

You have two identical neutral metal spheres labeled A and B, mounted on insulating posts, and you have a plastic pen that charges negatively when you rub it on your hair (Figure 14.77).


(a) (+ and −) Explain in detail, including diagrams, what operations you would carry out to give sphere A some positive charge and sphere B an equal amount of negative charge. (b) (+ and +) Explain in detail, including diagrams, what operations you would carry out on the neutral spheres to give sphere A some positive charge and sphere B an equal amount of positive charge (the spheres are initially uncharged).

: A thin, hollow spherical plastic shell of radius \({\bf{R}}\)carries a uniformly distributed negative charge \({\bf{ - Q}}\). A slice through the plastic shell is shown in Figure 14.95. To the left of the spherical shell are four charges packed closely together as shown (the distance \({\bf{s}}\) is shown greatly enlarged for clarity). The distance from the center of the four charges to the center of the plastic shell is \({\bf{L}}\) , which is much larger than \({\bf{s}}\left( {{\bf{L}} \gg {\bf{s}}} \right)\). Remember that a uniformly charged sphere makes an electric field as though all the charge were concentrated at the center of the sphere.

(a)Calculate the \({\bf{x}}\) and \({\bf{y}}\) components of the electric field at location B, a distance \({\bf{b}}\) to the right of the outer surface of the plastic shell. Explain briefly, including showing the electric field on a diagram. Your results should not contain any symbols other than the given quantities \({\bf{R,Q,q,s,L}}\), and \({\bf{b}}\)(and fundamental constants). You need not simplify the final algebraic results except for taking into account the fact that \({\bf{L}} \gg {\bf{s}}\).

(b)What simplifying assumption did you have to make in part (a)?

(c)The plastic shell is removed and replaced by an uncharged metal ball, as in Figure 14.96. At location Ainside the metal ball, a distance \({\bf{b}}\)to the left of the outer surface of the ball, accurately draw and label the electric field\({{\bf{\vec E}}_{{\bf{ball}}}}\) due to the ball charges and the electric field \({{\bf{\vec E}}_{\bf{4}}}\) of the four charges. Explain briefly.

(d)Show the distribution of ball charges.

(e)Calculate the \({\bf{x}}\) and \({\bf{y}}\) components of the net electric field at location A.

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