A student asked, "Since the positive nucleus of the atom is hidden inside a negative electron cloud, why doesn't all matter appear to be negatively charged?" Explain to the student the flaw in this reasoning.

Short Answer

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The atom becomes neutral because of the polarization of both the positive and the negative charges. The electron is centrally located in the nucleus. However, if the electron is centrally positioned, the proton field will be canceled by the electrons and it will create its own field. Thus, the atom appears as a neutral atom rather than a negatively charged atom.

Step by step solution

01

Significance of the polarization

The polarization is described as the property of the electromagnetic radiations, that helps to relate specifically the magnitude and the direction of an electric field.

02

Explanation the student the flaw in this reasoning

The statement states that when a positive nucleus mainly hides inside a negative cloud of the electron, then the positive electron should also appear negatively but it works differently as in the atom, the nucleus and the electron cloud move to each other. However, the atom becomes neutral because of the polarization of both the positive and the negative charges. The electron is centrally located in the nucleus. However, if the electron is centrally positioned, the proton field will be canceled by the electrons and it will create its own field. Hence, the atom appears as a neutral atom rather than a negatively charged atom.

Thus, the atom becomes neutral because of the polarization of both the positive and the negative charges. The electron is centrally located in the nucleus. However, if the electron is centrally positioned, the proton field will be canceled by the electrons and it will create its own field. Hence, the atom appears as a neutral atom rather than a negatively charged atom.

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Most popular questions from this chapter

(a)The positively charged particle shown in diagram 1 in Figure 14.94 creates an electric field \({{\bf{\vec E}}_{\bf{p}}}\) at location A. Which of the arrows (aj) in Figure 14.94 best indicates the direction of \({{\bf{\vec E}}_{\bf{p}}}\) at location A?

(b)Now a block of metal is placed in the location shown in diagram 2 in Figure 14.94. Which of the arrows (aj) in Figure 14.94 best indicates the direction of the electric field \({{\bf{\vec E}}_{\bf{m}}}\) at location Adue only to the charges in and/or on the metal block?

(c)\(\left| {{{{\bf{\vec E}}}_{\bf{p}}}} \right|\)is greater than \(\left| {{{{\bf{\vec E}}}_{\bf{m}}}} \right|\). With the metal block still in place, which of the arrows (aj) in Figure 14.94 best indicates the direction of the net electric field at location A?

(d)With the metal block still in place, which of the following statements about the magnitude of \({{\bf{\vec E}}_{\bf{p}}}\), the field due only to the charged particle, is correct?

(1) \(\left| {{{{\bf{\vec E}}}_{\bf{p}}}} \right|\)is less than it was originally, because the block is in the way.

(2) \(\left| {{{{\bf{\vec E}}}_{\bf{p}}}} \right|\)is the same as it was originally, without the block.

(3) \(\left| {{{{\bf{\vec E}}}_{\bf{p}}}} \right|\)is zero, because the electric field due to the particle can’t go through the block.

(e)With the metal block still in place, how does the magnitude of\({{\bf{\vec E}}_{{\bf{net}}}}\) at location Acompare to the magnitude of \({{\bf{\vec E}}_{\bf{p}}}\)?

(f)Which of the arrows (aj) in Figure 14.94 best indicates the direction of the net electric field at the center of the metal block (inside the metal)?

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