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Chapter 16: Q21P (page 663)

Question: If the kinetic energy of an electron is 4.4×10-18J, what is the speed of the electron? You can use the approximate (non relativistic) equation here.

Short Answer

Expert verified

Answer

The speed of the electron is 3.11×106m/s.

Step by step solution

01

Identification of the given data  

The given data can be listed below as,

  • The kinetic energy of an electron is, KE=4.4×10-18J.
02

Significance of kinetic energy

In this problem, the concept of a non-relativistic equation of kinetic energy will be used in order to estimate an electron's speed. The relation between the electron’s kinetic energy and electron mass is direct linear.

03

Determination the speed of an electron

The relation of kinetic energy of an electron is expressed as,

KE=12mev2

Here,me is the mass of an electron whose value is 9.1×10-31kgand is the speed of the electron.

Substitute all the known values in the above equation.

4.4×10-18J=129.1×10-31kgv2v2=24.4×10-18J9.1×10-31kg≈9.67032×1012J/kg1m2/s21J/kgv≈3.11×106m/s

Thus, the speed of the electron is 3.11×106m/s.

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Most popular questions from this chapter

Four voltmeters are connected to a circuit as shown in figure 16.90. As is usual with voltmeters, the reading on the voltmeter is positive if the negative lead (black wire, usually labled COM) is connected to a location at lower potential, and the positive lead(red) is connected to a location at higher potential. The circuit contains two devices whose identity is unknown and a rod (green) of length 9 cm made of conducting material. At a particular moment, the reading observed in the voltmeters are, voltmeter A: -1.6 V, voltmeter B: -6 V, voltmeter A: -3.5 V. (a) At this moment, what is the reading on voltmeter D, both magnitude and sign? (b) What are the magnitude and direction of the electric field inside the rod?

Figure 16.60 shows a portion of a long, negatively charged rod. You need to calculate the potential differenceVA-VB.

(a) What is the direction of the path (+y or −y)? (b) What is the sign of VA-VB?

An electron starts from rest in a vacuum, in a region of strong field. The electron moves through a potential difference of 44V. (a) What is the kinetic energy of the electron in electron volts (eV)? (b) Which of the following statements would be true if the particle were a proton? Choose both if they are both correct. (1) The kinetic energy of the proton would be negative. (2) The proton would move in the opposite direction from the electron.

Location C is0.02m from a small sphere that has a charge of4nCuniformly distributed on its surface. Location D is0.06mfrom the sphere. What is the change in potential along a path from C to D?

A Student said, “The electric field at the center of a charged spherical shell is zero, so the potential at that location is also zero.” Explain to the student why this statement is incorrect.
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