Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 16: Q27P (page 663)

A capacitor with a gap of 1mm has a potential difference from one plate to the other of36V . What is the magnitude of the electric field between the plates?

Short Answer

Expert verified

The magnitude of the electric field between the plates is36×103 V/m .

Step by step solution

01

Identification of the given data

The given data can be listed below as,

  • The gap between a capacitor plates is, d=1 mm ×10−3 m1 mm=10−3 m.
  • The potential difference from one plate to the other is, V=36 V.
02

Significance of parallel plate capacitor

Whenever two parallel conducting plates lie parallel at a specific distance and connect with a particular potential difference, this arrangement refers to a parallel plate capacitor.

03

Determination the magnitude of the electric field between the plates

The relation of the magnitude of the electric field between the plates is expressed as,

E=Vd

Here, E is the magnitude of the electric field between the plates.

Substitute all the known values in the above equation.

E=36 V10−3 m=36×103 V/m

Thus, the magnitude of the electric field between the plates is 36×103 V/m.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A thin spherical shell of radius \({R_1}\)made of plastic carries a uniformly distributed negative charge \( - {Q_1}\). A thin spherical shell of radius \({R_2}\)made of glass carries a uniformly distributed positive charge \( + {Q_2}\). The distance between centers is \(L\), as shown in Figure 16.80. (a) Find the potential difference \({V_B} - {V_A}\). Location A is at the center of the glass sphere, and location \(B\) is just outside the glass sphere. (b) Find the potential difference \({V_C} - {V_B}\). Location \(B\) is just outside the glass sphere, and location \(C\) is a distance d to the right of \(B\). (c) Suppose the glass shell is replaced by a solid metal sphere with radius R2 carrying charge \( + {Q_2}\). Would the magnitude of the potential difference \({V_B} - {V_A}\) be greater than, less than, or the same as it was with the glass shell in place? Explain briefly, including an appropriate physics diagram.

15,000VIn the cathode ray tube found in old television sets, which contains a vacuum, electrons are boiled out of a very hot metal filament placed near a negative metal plate. These electrons start out nearly at rest and are accelerated toward a positive metal plate. They pass through a hole in the positive plate on their way toward the picture screen, as shown in the diagram in Figure 16.69. If the high-voltage supply in the television set maintains a potential difference of 15,000Vbetween the two plates, what speed do the electrons reach?

As shown in Figure 16.72, three large, thin, uniformly charged plates are arranged so that there are two adjacent regions of uniform electric field. The origin is at the center of the central plate. Location A is <-0.4,0,0>m, and location B is<0.2,0,0>m . The electric fieldE1→ has the value <725,0,0>V/m, and E2→is <-425,0,0>V/m.

(d) What is the minimum kinetic energy the electron must have at location A in order to ensure that it reaches location B?

Locations A and B are in a region of uniform electric field, as shown in Figure 16.67. Along a path from B to A, the change in potential is-2200V. The distance from A to B is 0.28m. What is the magnitude of the electric field in this region?

If the kinetic energy of an electron is 4.4×10-18J, what is the speed of the electron? You can use the approximate (non relativistic) equation here.
See all solutions

Recommended explanations on Physics Textbooks

Electricity

Read Explanation

Work Energy and Power

Read Explanation

Atoms and Radioactivity

Read Explanation

Famous Physicists

Read Explanation

Energy Physics

Read Explanation

Fundamentals of Physics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free