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Chapter 16: Q33P (page 663)

Locations A and B are in a region of uniform electric field, as shown in Figure 16.67. Along a path from B to A, the change in potential is-2200V. The distance from A to B is 0.28m. What is the magnitude of the electric field in this region?

Short Answer

Expert verified

The magnitude of the electric field is7857.143N/C

Step by step solution

01

Change in the electric potential energy

The magnitude of the electric field for a charged particle (positive or negative) relies on the change in the electric potential energy of that particle.

Also, the potential energy change with the amount of distance the particle travels in the electric filed.

02

Given data

The change in the potential from B to A is,ΔVBA=-2200 V. .

The distance from A to B is, ΔlAB=0.28 m.

03

The magnitude of the electric field

Theformula for the magnitude of the electric field in the regionis given by,

ΔVBA=-E×ΔIABE=ΔVBAΔIABE=--2200 V0.28m×1N/C1V/mE=7857.143N/C

Hence, the magnitude of the electric field is 7857.143 N/C.

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Most popular questions from this chapter

You travel along a path from location A to location B, moving in a direction opposite to the direction of the net electric field in that region. What is true of the potential difference VB-VA?(1)VB-VA>0,(2)VB-VA<0,(3)VB-VA=0.

Four voltmeters are connected to a circuit as shown in figure 16.90. As is usual with voltmeters, the reading on the voltmeter is positive if the negative lead (black wire, usually labled COM) is connected to a location at lower potential, and the positive lead(red) is connected to a location at higher potential. The circuit contains two devices whose identity is unknown and a rod (green) of length 9 cm made of conducting material. At a particular moment, the reading observed in the voltmeters are, voltmeter A: -1.6 V, voltmeter B: -6 V, voltmeter A: -3.5 V. (a) At this moment, what is the reading on voltmeter D, both magnitude and sign? (b) What are the magnitude and direction of the electric field inside the rod?

LocationsA=<a,0,0>andB=<b,0,0>are on the +x axis, as shown in Figure 16.61. Four possible expressions for the electric field along the x axis are given below. For each expression for the electric field, select the correct expression (1–8) for the potential differenceVA-VB. In each case K is a numerical constant with appropriate units.

(a)E→=<Kx2,0,0>(b)E→=<Kx3,0,0>(c)E→=<Kx,0,0>(b)E→=<Kx,0,0>(1)VA-VB=0(2)VA-VB=K(a-b)(3)VA-VB=K(1a-1b)(4)VA-VB=K(1a3a-1b3b)(5)VA-VB=12K(b2-a2)(6)VA-VB=KIn(ba)(7)VA-VB=K(a3-b3)(8)VA-VB=12K(1a2-1b2)

The graph in Figure 16.63 is a plot of electric potential versus distance from an object. Which of the following could be the object?

(1) A neutron, (2) A sodium ion (Na+), (3) A chloride ion (Cl−), (4) A proton, (5) An electron.

A rod uniformly charged with charge \( - q\) is bent into a semicircular arc of radius\(b\), as shown in Figure 16.97. What is the potential relative to infinity at location\(A\), at the center of the arc?
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