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Chapter 16: Q36P (page 663)

A capacitor with a gap of 2 mm has a potential difference from one plate to the other of 30 V. What is the magnitude of the electric field between the plates?

Short Answer

Expert verified

The electric field between the two plates is -15000 N/C.

Step by step solution

01

Electric field between plates

A conductor having two parallel plates with a certain amount of gap consists of an electric field between the plates.

The value of this electric field present between the plates relies on the gap between plates as well as the potential difference between them

02

Given data

The gap between the capacitor plates is, Δl=2 mm×1 m1000mm=0.002 m.

The potential difference between plates is, ΔV=30 V.

03

The electric field between the plates

The formula for the magnitude of the electric field between the two plates of a capacitor is given by,

E=-ΔVΔlE=-30 V0.002 m×1 N/C1 V/mE=-15000 N/C

Hence, the electric field between the two plates is -15000N/C.-15000N/C.

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Most popular questions from this chapter

Question: If the kinetic energy of an electron is 4.4×10-18J, what is the speed of the electron? You can use the approximate (non relativistic) equation here.

2 Three charged metal disks are arranged as shown in Figure 16.75 (cutaway view). The disks are held apart by insulating supports not shown in the diagram. Each disk has an area of 2.5 m2 (this is the area of one flat surface of the disk). The charge Q1=5×10-8Cand the charge Q2=4×10-7 C.

(a) What is the electric field (magnitude and direction) in the region between disks 1 and 2? (b) Which of the following statements are true? Choose all that apply. (1) Along a path from A to B, E→⊥ΔI→(2) VB-VA=0.(3) localid="1657088862802" VB-VA=-Q/2.5ε0+(0.003) V. . (c) To calculateVC-VB , where should the path start and where should it end? (d) Shouldlocalid="1657089209063" VC-VB be positive or negative? Why? (1) Positive, because localid="1657089087291" ΔI→is opposite to the direction of . (2) Negative, becauseΔI→ is in the same direction asE→ . (3) Zero, becauseΔI→⊥E→. (e) What is the potential differenceVC-VB ? (f) What is the potential differenceVD-VC ? (g) What is the potential differenceVF-VD ? (h) What is the potential differenceVG-VF ? (i) What is the potential differenceVG-VA? (j) The charged disks have tiny holes that allow a particle to pass through them. An electron that is traveling at a fast speed approaches the plates from the left side. It travels along a path from A to G. Since no external work is done on system of plates + electron, ΔK+ΔU=Wext=0. Consider the following states: initial, electron at location A; final, electron at location G. (1) What is the change in potential energy of the system? (2) What is the change in kinetic energy of the electron?

You move from location i at ⟨2,5,4⟩ mto location f at ⟨3,5,9⟩ m. All along this path there is a nearby uniform electric field whose value is⟨1000,200,-500⟩ N/C. . Calculate,ΔV=Vf-Vi including signs and units.

The diagram in Figure 16.74 shows three very large metal disks (seen edgewise), carrying charges as indicated. On each surface the charges are distributed approximately uniformly. Each disk has a very large radius R and a small thickness t. The distances between the disks are a and b, as shown; they also are small compared to R. Calculate V2-V1, and explain your calculation briefly.

Question: An electron passes through a region in which there is an electric field, and whiles it is in the region its kinetic energy decreases by 4.5×10-17J. Initially the kinetic energy of the electron was4.5×10-17J . What is the final speed of the electron? (You can use the approximate (nonrelativistic) equation here.)
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