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Chapter 8: Q13P (page 344)

The Frank Hertz experiment involved shooting electrons into a low density gas of mercury atoms and observing discrete amounts of kinetic energy loss by the electrons. Suppose that instead the similar experiment is done with a very cold gas of atomic hydrogen, so that all of the hydrogen atoms are initially in ground state. If the kinetic energy of an electron is 11.6 eV just before it collides with a hydrogen atom. How much kinetic energy will the electron have just after it collides with and excites the hydrogen atom?

Short Answer

Expert verified

The kinetic energy of electron after collision is1.4eV .

Step by step solution

01

Identification of given data

The kinetic energy of electron just before collision isKi=11.6eV

02

Conceptual Explanation

The electron loses it kinetic energy just after collision with atomic hydrogen and kinetic energy of electron just after collision will be equal to the difference between kinetic energy before collision and energy of hydrogen atom in first excited state.

03

Determination of kinetic energy of electron after collision

The kinetic energy of electron just after collision is given as:

Kf=Ki-Ee

Here, Ee is the energy of hydrogen in first excited state and its value is 10.2eV

Substitute all the values in the above equation.

Kf=11.6eV-10.2eVKf=1.4eV

Therefore, the kinetic energy of electron just after collision is 1.4eV.

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