Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 12: Q7 CP (page 488)

There was transfer of energy of 5000 J into a system due to a temperature difference, and the entropy increased by 10 J/K. What was the approximate temperature of the system, assuming that the temperature didn’t change very much?.

Short Answer

Expert verified
  • The approximate temperature of the system is 500K

Step by step solution

01

Identification of given data

  • The energy transferred isQ=5000J.
  • The increase in entropy isS=10J/K.
02

Concept of entropy

A condition of disorder, unpredictability, or uncertainty is usually related to the scientific notion of entropy, which is also a physical characteristic that can be measured.

The entropy of a system is given by,

S=QT…… (i)

Here Qis the energy transfer of the system.

Tis the temperature change of the system.

03

Determination of the change in temperature

The change in temperature can be evaluated using equation (i),

10J/K=5000JTT=500010·1J1J/KT=5001KT=500K

Thus, the change in temperature of the system is found to be 500K.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Buckminsterfullerene, C60, is a large molecule consisting of 60 carbon atoms connected to form a hollow sphere. The diameter of a C60 molecule is about 7×10-10 m. It has been hypothesized that C60 molecules might be found in clouds of interstellar dust, which often contain interesting chemical compounds. The temperature of an interstellar dust cloud may be very low; around 3 K. Suppose you are planning to try to detect the presence of C60 in such a cold dust cloud by detecting photons emitted when molecules undergo transitions from one rotational energy state to another. Approximately, what is the highest-numbered rotational level from which you would expect to observe emissions? Rotational levels are l= 0, 1, 2, 3, …

Calculate vmsfor a helium atom and for a nitrogen molecule ( N2; molecular mass 28g/mol) in the room you’re in (whose temperature is probably about 293K).

What is the advantage of plotting the (natural) logarithm of the number of ways of arranging the energy among the many atoms (natural logarithm of the number of microstates)?

Figure 12.59 shows the distribution of speeds of atoms in a particular gas at a particular temperature. Approximately what is the average speed? Is the RMS (root-mean-square) speed bigger or smaller than this? Approximately what fraction of the molecules have speeds greater than 1000 m/s?

At room temperature, show that KBT≈1/ 40 eV. It is useful to memorize this result, because it tells a lot about what phenomena are likely to occur at room temperature.
See all solutions

Recommended explanations on Physics Textbooks

Electric Charge Field and Potential

Read Explanation

Quantum Physics

Read Explanation

Conservation of Energy and Momentum

Read Explanation

Force

Read Explanation

Fields in Physics

Read Explanation

Torque and Rotational Motion

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free