There was transfer of energy of 5000 J into a system due to a temperature difference, and the entropy increased by 10 J/K. What was the approximate temperature of the system, assuming that the temperature didn’t change very much?.

Short Answer

Expert verified
  • The approximate temperature of the system is 500K

Step by step solution

01

Identification of given data

  • The energy transferred isQ=5000J.
  • The increase in entropy isS=10J/K.
02

Concept of entropy

A condition of disorder, unpredictability, or uncertainty is usually related to the scientific notion of entropy, which is also a physical characteristic that can be measured.

The entropy of a system is given by,

S=QT…… (i)

Here Qis the energy transfer of the system.

Tis the temperature change of the system.

03

Determination of the change in temperature

The change in temperature can be evaluated using equation (i),

10J/K=5000JTT=500010·1J1J/KT=5001KT=500K

Thus, the change in temperature of the system is found to be 500K.

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Most popular questions from this chapter

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