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Chapter 12: Q7CP (page 488)

There was transfer of energy of 5000 J into a system due to a temperature difference, and the entropy increased by 10 J/K. What was the approximate temperature of the system, assuming that the temperature didn’t change very much?

Short Answer

Expert verified
  1. The approximate temperature of the system is 500 K .

Step by step solution

01

Identification of given data

  • The energy transferred is Q=5000 J.
  • The increase in entropy is S=10 J/K.
02

Concept of entropy

A condition of disorder, unpredictability, or uncertainty is usually related to the scientific notion of entropy, which is also a physical characteristic that can be measured.

The entropy of a system is given by,

S=QT…… (i)

Here Q is the energy transfer of the system.

is the temperature change of the system.

03

Determination of the change in temperature

The change in temperature can be evaluated using equation (i),

10J/K=5000JTT=500010.1J1J/KT=500.1KT=500K

Thus, the change in temperature of the system is found to be 500 K .

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Most popular questions from this chapter

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