At room temperature, show that KBT≈1/ 40 eV. It is useful to memorize this result, because it tells a lot about what phenomena are likely to occur at room temperature.

Short Answer

Expert verified

The result can be proved using the energy equation.

Step by step solution

01

Identification of given data

  • Boltzmann’s constant iskb=8.62×10-5eVK .
  • The room temperature isT=20°C=293K .
02

Concept of energy

The ability to do tasks is known as energy. Depending on the form it takes, it may be either potential or kinetic or thermal or electrical or chemical, or nuclear.

The energy equation is given by,

E=kbT…… (i)

Here kbis Boltzmann’s constant.

Tis the room temperature.

03

Evaluation of energy equation

The energy equation can be proved using equation (i)

E=8.62×105eVK×293KE=8.62×10-5×293.1eV1K×1KE=0.025eVE140eV

Thus, the temperature equation is proved.

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