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Chapter 1: 13P (page 39)

Question: What is the magnitude of the vector v, where v=(8×106,0,-2×107)m/s?

Short Answer

Expert verified

Answer

Magnitude of given vector is 21.54×106m/s

Step by step solution

01

Formula used

Magnitude of a vector ahaving coordinates (x,y,z)is given by|a|=x2+y2+z2. The magnitude of a vector gives the length of the vector so, basically magnitude is used to find the length of a vector between the initial and the final point of the vector.

02

Calculation of magnitude

Substitute x=8×106,y=0and z=-2×107into the formula of magnitude to get the magnitude of the given vector.

|v|=(8×106)2+02+(-2×107)2=(64×1012)+0+(4×1014)=464×1012=21.54×106m/s

Thus, the magnitude of the given vector vis 21.54×106m/s.

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Most popular questions from this chapter

After World War II the U.S. Air Force carried out experiments on the amount of acceleration a human can survive.These experiments led by Jon Stapp, were the first to use crash dummies as well as human subjects, especially Stapp himself, who became an effective advocate for automobile safety belts. In one of the experiments Stapp rode a rocket sled that decelerated from 140m/s(about 310mil/h) to 70m/sin just 0.6s. What was the absolute value of the (negative) average acceleration? (b) The acceleration of a falling object if air resistance is negligible is 9.8m/s/s,called “one g.” What was the absolute value of the average acceleration in gas? What was the absolute value of the average acceleration in g’s? (Stapp eventually survived a test at 46g's!)

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