A basketball has a mass of 570 g. Moving to the right and heading downward at an angle of 30 to the vertical, it hits the floor with the speed of 5 m/s and bounces up with nearly the same speed, again moving to the right an angle of 30 degree to the vertical. What was the momentum changep?

Short Answer

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Answer

The momentum change will be ( 0,4.93,0) kg .m/s

Step by step solution

01

Identification of given data

The given data listed below as,

  • Mass of the basketball m= 570 g = 0.57 kg,.
  • Velocity, v = 5m/s.
  • θ=30°
02

The momentum change 

It bounces up with the same speed, again moving to the right at an angle of 30 degrees to the vertical. We need to find the change in momentum.

03

 Step 3: Calculation for the momentum change

For the change in momentum, this will become:

p=mvcosθ--mvcosθp=2mvcosθ

Substituting the values and we get,

p=2×0.57kg×m/s×cos30°=4.93kg.m/s

The change will be in the y-direction only.

Hence, the momentum change will be.

0,4.93,0kg.m/s

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Most popular questions from this chapter

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(a) Which of the following do you see moving with constant velocity? (1) A ship sailing northeast at a speed of 5 meters per second (2) The Moon orbiting the Earth (3) A tennis ball traveling across the court after having been hit by a tennis racket (4) A can of soda sitting on a table (5) A person riding on a Ferris wheel that is turning at a constant rate. (b) In which of the following situations is there observational evidence for significant interaction between two objects? How can you tell? (1) A ball bounces off a wall with no change in speed. (2) A baseball that was hit by a batter flies toward the outfield. (3) A communications satellite orbits the Earth. (4) A space probe travels at constant speed toward a distant star. (5) A charged particle leaves a curving track in a particle detector.

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