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Chapter 1: Q8CP (page 15)

At 10:00 AM you are at the location-3,2,5m. By 10:02 AM you have walked to location6,4,25m. (a) What is ∆r→, the change in your position? (b) What is∆t , the time interval during which your position changed?

Short Answer

Expert verified

(a) Change in position is ∆r→=9,2,20m

(b) Time interval is localid="1653483524995" ∆t=120s

Step by step solution

01

Define the formula for the change in position

The formula for∆r→ is∆r→=r→f-r→i where stands for final position and stands for initial position.

The formula for∆t is∆t=tf-ti where, stands for final time and stands for initial time.

02

Finding change in position

(a)

Substitute r→f=-3,2,5m and r→i=6,4,25m into the formula of ∆r→to obtain the change in position.

role="math" localid="1653482961357" ∆r→=6--3,4-2,25-5=9,2,20m

Therefore, the change in position is 9,2,20m.

03

Finding time interval

From the given information, tf= 10 : 02 AM and ti= 10 : 00 AM

Subtract initial time from the final time to obtain the time interval.

∆t= 120 s

Thus, the time interval is 120 s.

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Most popular questions from this chapter

Consider the vectors r1→and r2→represented by arrows in Figure 1.20. Are these two vectors equal? (b) If a→=<400,200-100>m/s2,and c→=a→, what is the unit vector c^in the direction of c^?

Figure 1.20

A baseball has a mass of 0.155 kg . A professional pitcher throws a baseball 90 mill/h ,which is 4om/s.What is the magnitude of the momentum of the pitched baseball?

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Here are the positions of the ball at several successive times.

Location

t(s)

Position ( m)

A

0.0

(0,0,0)

B

1.0

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C

2.0

(40.1,38.1,0)

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