The center of a bar magnet whose magnetic dipole moment is 8,0,0 Am2is located at the origin. A second bar magnet whose magnetic dipole moment is 3,0,0 Am2is located at x=0.12 m. What is the vector force on the second magnet due to the first magnet?

Short Answer

Expert verified

The vector force on the second magnet due to the first magnet is6.94×102 N

Step by step solution

01

Given Information

The dipole moment is given by μ1=8,0,0 Am2at location 0,0,0and μ2=3,0,0 Am2at location 0.12,0,0 m0.12,0,0 m

02

Force of Attraction and Repulsion

It is known that two magnets should attract or repel each other with a force proportional to 1r4and the attractive or repulsive force exert on a magnetic dipole moment by this magnet is given as:

F=3μ2μ04π2μ1r4                 1

03

Calculate the vector force

Now substitute the value μ1=8,μ2=3and r=0.12in equation (1),

F=3μ2μ04π2μ1r4=331×107280.124=6.94×102 N

Thus, the vector force on the second magnet due to the first magnet is 6.94×102 N.

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