Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 6: Q19P (page 277)

You push a crate3 m across the floor with aforce whose direction is30° below the horizontal. How much work do you do?

Short Answer

Expert verified

Work done after pushing the crate across the floor is 104 N m.

Step by step solution

01

Definition of the work done

Work is the force times the displacement of the item and is the quantity of energy transferred between a source of applied force and the object that this force affects.

The work done as a result of the force is given by orW=F⇀.∆rorW=F⇀r⇀cosθ .

02

Finding work done

Substitute F=40N,∆r=3mθ=30°, into the formula of work done.

W=40×3×cos30°=603=104Nm

Therefore, work done after pushing the crate across the floor is 104Nm.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An automobile traveling on a highway has an average kinetic energy of . Its mass is . What is its average speed? Convert your answer to miles per hour to see whether it makes sense. If you could use all of themc2rest energy of some amount of fuel to provide the car with its kinetic energy of , What mass of fuel would you need?

A comet is in elliptical orbit around the Sun. Its closest approach to the Sun is a distance of 4×1010m (inside the orbit of Mercury), at which point its speed is 8.17×104m/s. Its farthest distance from the Sun is far beyond the orbit of Pluto. What is its speed when it is 6×1012m from the Sun? (This is the approximate distance of Pluto from the Sun.)

Refer to figure 6.86. Calculate the change in electric energy along the two different paths in moving charge qaway from charge Q from A to B along a radial path, then to C along a circle centeredon Q , then to D along a radial path. Also calculate the change in energy in going directly from A to D along a circle centered at Q. Specifically. What are UB-UA,UC-UB,UD-UCand their sum? What is UD-UA? Also, calculate the round-trip difference in the electrical energy when moving charge along the path from A to B to C to D to A.

n electron is travelling at a speed of 0.95cin an electron accelerator. An electric force of 1.6×10-13Nis applied in the direction of motion while the electron travels a distance of 2m. What is the new speed of the electron?

In the preceding example, at the final speed, 0.9997 c, what was the particle energy as a multiple of the rest energymc2 ? (That is, if it was twice mc2, writemc2 .) What was the kinetic energy as a multiple ofmc2? Was the kinetic energy large or small compared to the rest energy? At low speeds, is the kinetic energy large or small compared to the rest energy?
See all solutions

Recommended explanations on Physics Textbooks

Physics of Motion

Read Explanation

Magnetism and Electromagnetic Induction

Read Explanation

Electromagnetism

Read Explanation

Waves Physics

Read Explanation

Fundamentals of Physics

Read Explanation

Measurements

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free