Show that the units ofP22m andmc2are indeed joules.

Short Answer

Expert verified

Both the termsp22m andmc2 have the same unit, which is Joule

Step by step solution

01

Formula of energy

The particle’s energy is given by:

E=p22m

Here,is the momentum of the particle andis the mass of the particle inkg.

The momentum is given by:

Here is mass, and is the velocity of the particle.

02

Evaluate the first equation

Use the formula of momentum into the formula of energy.

E=mv22m=12mv2

Therefore, it is safe to say thatp22m is equal to 12mv2.

03

Finding the unit of p22m

Find the unit of the quantity p22mand use kgm/s2=N,

1kg1m/s22=1kg1m/s1m=1kg1m/s21m×1N1kgm/s=1Nm×1J1Nm=1J

04

Finding the unit of mc2

The formulamc2presents the rest energy of the particle where c is the velocity of light and its unit ism/s.

Find the unit of the quantity mc2 and usekgm/s2=N.

1kg1m/s=1kg1m/s1m=1kg1m/s21m×1N1kgm/s=1Nm×1J1Nm=1J

Therefore, both the termsp22m and mc2 have the same unit, which is .

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Most popular questions from this chapter

In the preceding example, at the final speed, 0.9997 c, what was the particle energy as a multiple of the rest energymc2 ? (That is, if it was twice mc2, writemc2 .) What was the kinetic energy as a multiple ofmc2? Was the kinetic energy large or small compared to the rest energy? At low speeds, is the kinetic energy large or small compared to the rest energy?

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This is one of the thermonuclear or fusion reactions that takes place inside a star such as our Sun.

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